X459

X253-CEVA CONJUGATE OF X4

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 4, 64 }: Central Line L(4, 64) { 2, 253 }: Central Line L(2, 253) { 196, 226 }: Central Line L(196, 226) { 69, 801 }: Central Line L(69, 801) { 98, 1301 }: Central Line L(98, 1301) { 92, 1446 }: Central Line L(92, 1446) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_253 = -CROSS CONJUGATE OF X(2) (3.5087, 32.5688) X_4 = ORTHOCENTER (0.6122, 0.3958) X_64 = ISOGONAL CONJUGATE OF X(20) (0.5579, 1.5943) X_2 = CENTROID (0.5374, 0.2000) X_196 = -CEVA CONJUGATE OF X(4) (0.5649, -0.1989) X_226 = -CEVA CONJUGATE OF X(65) (0.5778, 0.2588) X_69 = SYMMEDIAN POINT OF THE ANTICOMPLEMENTARY TRIANGLE (0.4122, 0.0654) X_801 = ISOGONAL CONJUGATE OF X(800) (0.4263, 0.1232) X_98 = TARRY POINT (0.8891, -0.2281) X_1301 = COLLINGS TRANSFORM OF X(235) (0.6568, 0.5877) X_92 = CEVAPOINT OF INCENTER AND CLAWSON POINT (0.5949, 0.3639) X_1446 = -BETH CONJUGATE OF X(349) (0.5951, 0.3031) X_459 = -CEVA CONJUGATE OF X(4) (0.5934, 0.8103) A B C X253 X4 X64 X2 X196 X226 X69 X801 X98 X1301 X92 X1446 X459 (a, b, c) = (5, 6, 7) | AB = 1

X459 (X253-CEVA CONJUGATE OF X4) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \((\sec A)/(\tan B + \tan C - \tan A) : :\)
Barycentrics: \(1/(\tan B \tan C - 2) : :\)
Search Value (6, 9, 13): \(1.857177179962\)
▸ Alternate Coordinates2 forms
  • Trilinears: \(|A'A''| : :\), where A'B'C', A″B″C″ are the cevian and anticevian triangles of X4

  • Barycentrics: \(1/(S_{A}(S^{2} - 2S_{B}S_{C})) : :\)

X459 lies on the Kiepert hyperbola.

▸ Incident Central Lines20 lines

{2, 253}, {4, 64}, {10, 3176}, {25, 3424}, {69, 801}, {92, 1446}, {96, 3147}, {98, 1301}, {154, 5922}, {196, 226}, {262, 3168}, {297, 2996}, {458, 5395}, {485, 3535}, {486, 3536}, {1075, 3090}, {1131, 1585}, {1132, 1586}, {1503, 3079}, {5485, 5523}

▸ Functional Relations11 relations

Notes

Let A'B'C' be the midheight triangle. Let A″ be the pole, wrt the polar circle, of line B'C', and define B″ and C″ cyclically. The lines AA″, BB″, CC″ concur in X459. (Randy Hutson, June 7, 2019)