X1577¶
ISOGONAL CONJUGATE OF X163
X1577 (ISOGONAL CONJUGATE OF X163) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).¶
Constructed Elements
Central Lines: {240, 522}, {1, 810}
Related Centers: X163 (TRILINEAR PRODUCT X6*X110), X240 (-LINE CONJUGATE OF X48), X522 (ISOGONAL CONJUGATE OF X109), X1 (INCENTER), X810 (CROSSPOINT OF X1 AND X163)
Alternate Coordinates4 forms
Trilinears: \((\csc 2A)(\sin 2B - \sin 2C) : :\)
Trilinears: \(d(a,b,c) : :\), where d(a,b,c) = directed distance from A to Brocard axis
Trilinears: \(|AP(1)|^{2} - |AU(1)|^{2} : :\)
Barycentrics: \(\sin(B - C) : \sin(C - A) : \sin(A - B)\)
Incident Central Lines9 lines
Functional Relations21 relations
X1577 = isotomic conjugate of X662
X1577 = Xi-Ceva conjugate of Xj for these (i,j): (75, 1109), (76, 1111), (693, 523), (799, 75), (811, 1), (823, 92)
X1577 = Xi-cross conjugate of Xj for these (i,j): (115, 1089), (1109, 75)
X1577 = crosspoint of Xi and Xj for these (i,j): (75, 799), (82, 162), (92, 823), (662, 2167), (811, 1969), (1240, 1978)
X1577 = crosssum of Xi and Xj for these (i,j): (31, 798), (38, 656), (48, 822), (649, 2260), (652, 2269), (661, 1953), (1923, 1924)
X1577 = crossdifference of every pair of points on line X31X48
X1577 = Xi-aleph conjugate of Xj for these (i,j): (648, 656), (811, 1969)
X1577 = complement of X4560
X1577 = bicentric difference of PU(14)
X1577 = trilinear product of PU(40)
X1577 = perspector of hyperbola {{A, B, C,X75,X92}} (centered at X4858)
X1577 = center of circumconic that is locus of trilinear poles of lines passing through X4858
X1577 = X6-isoconjugate of X110
X1577 = pole wrt polar circle of trilinear polar of X162 (line X1X19)
Notes¶
Let JaJbJc be the excentral triangle, and let U be the bianticevian conic of X1 and X4. Let T be the tangential triangle, wrt the anticevian triangle of X19, of U. Then JaJbJc and T are perspective, and their perspector is X1577. (Randy Hutson, December 26, 2015)
X1577 is the trilinear multiplier for the Kiepert hyperbola. (The trilinear product of X1577 and the circumcircle is the Kiepert hyperbola.) (Randy Hutson, August 19, 2019)