X219

X8-CEVA CONJUGATE OF X55

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 1, 6 }: Incenter–Symmedian Line { 8, 29 }: Central Line L(8, 29) { 3, 48 }: Central Line L(3, 48) { 63, 77 }: Central Line L(63, 77) { 101, 102 }: Central Line L(101, 102) { 55, 284 }: Central Line L(55, 284) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_8 = NAGEL POINT (0.4694, 0.1333) X_55 = INSIMILICENTER(CIRCUMCIRCLE, INCIRCLE) (0.5490, 0.1921) X_1 = INCENTER (0.5714, 0.2333) X_6 = SYMMEDIAN POINT (LEMOINE POINT, GREBE POINT) (0.6000, 0.2672) X_29 = CEVAPOINT OF INCENTER AND ORTHOCENTER (0.5903, 0.3384) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_48 = CROSSPOINT OF X(1) AND X(63) (0.5412, 0.1246) X_63 = ISOGONAL CONJUGATE OF X(19) (0.4566, 0.0823) X_77 = ISOGONAL CONJUGATE OF X(33) (0.5270, 0.1305) X_101 = Ψ(INCENTER, SYMMEDIAN POINT) (0.2143, 0.5249) X_102 = Λ(INCENTER, ORTHOCENTER) (0.6364, -0.3897) X_284 = -CROSS CONJUGATE OF X(21) (0.5646, 0.2088) X_219 = -CEVA CONJUGATE OF X(55) (0.4277, 0.0625) A B C X8 X55 X1 X6 X29 X3 X48 X63 X77 X101 X102 X284 X219 (a, b, c) = (5, 6, 7) | AB = 1

X219 (X8-CEVA CONJUGATE OF X55) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(\cos A \cot A/2 : :\)
Barycentrics: \(\sin 2A \cot A/2 : :\)
Search Value (6, 9, 13): \(4.717066795933\)
▸ Alternate Coordinates4 forms
  • Trilinears: \((\sin A)/(1 - \sec A) : :\)

  • Trilinears: \(1/(\csc A - 2 \csc 2A) : :\)

  • Trilinears: \(a(b + c - a)(b^{2} + c^{2} - a^{2}) : :\)

  • Trilinears: \((b + c - a) \cos A : :\)

▸ Incident Central Lines23 lines

{1, 6}, {3, 48}, {8, 29}, {10, 965}, {19, 517}, {40, 610}, {41, 1036}, {55, 284}, {56, 579}, {63, 77}, {69, 1332}, {101, 102}, {144, 347}, {200, 282}, {206, 692}, {255, 268}, {278, 329}, {332, 345}, {346, 644}, {572, 947}, {577, 906}, {604, 672}, {1993, 3219}

▸ Functional Relations15 relations

Notes

Let NaNbNc be the extouch triangle. Let A″ be the barycentric product of the circumcircle intercepts of line NbNc, and define B″ and C″ cyclically. The lines NaA″, NbB″, NcC″ concur in X219. (Randy Hutson, July 31 2018)