X2052

ISOGONAL CONJUGATE OF X577

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 4, 51 }: Central Line L(4, 51) { 24, 96 }: Central Line L(24, 96) { 25, 98 }: Central Line L(25, 98) { 10, 158 }: Central Line L(10, 158) { 2, 216 }: Central Line L(2, 216) { 6, 275 }: Central Line L(6, 275) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_577 = HARMONIC OF X(216) (0.4663, 0.0464) X_4 = ORTHOCENTER (0.6122, 0.3958) X_51 = CENTROID OF ORTHIC TRIANGLE (0.6093, 0.3186) X_24 = PERSPECTOR OF ABC AND ORTHIC-OF-ORTHIC TRIANGLE (0.6627, 0.5278) X_96 = ISOGONAL CONJUGATE OF X(52) (-0.0943, -0.0197) X_25 = HOMOTHETIC CENTER OF ORTHIC AND TANGENTIAL TRIANGLES (0.6329, 0.4497) X_98 = TARRY POINT (0.8891, -0.2281) X_10 = SPIEKER CENTER (0.5204, 0.1833) X_158 = -CROSS CONJUGATE OF X(92) (0.6215, 0.5117) X_2 = CENTROID (0.5374, 0.2000) X_216 = -CEVA CONJUGATE OF X(51) (0.5201, 0.1353) X_6 = SYMMEDIAN POINT (LEMOINE POINT, GREBE POINT) (0.6000, 0.2672) X_275 = CEVAPOINT OF ORTHOCENTER AND SYMMEDIAN POINT (0.6057, 0.3473) X_2052 = ISOGONAL CONJUGATE OF X(577) (0.6161, 0.4941) A B C X577 X4 X51 X24 X96 X25 X98 X10 X158 X2 X216 X6 X275 X2052 (a, b, c) = (5, 6, 7) | AB = 1

X2052 (ISOGONAL CONJUGATE OF X577) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(\csc A \sec^{2} A : :\)
Barycentrics: \(\sec^{2} A : :\)
Search Value (6, 9, 13): \(1.329869583541\)
▸ Alternate Coordinates3 forms
  • Trilinears: \(\sec A \csc 2A : :\)

  • Trilinears: \(\sec(A - T) : :\), T as at X389

  • Barycentrics: \(b^{2}c^{2}/(b^{2} + c^{2} - a^{2})^{2} : :\)

▸ Incident Central Lines22 lines

{2, 216}, {4, 51}, {6, 275}, {10, 158}, {13, 473}, {14, 472}, {17, 470}, {18, 471}, {24, 96}, {25, 98}, {63, 1947}, {76, 297}, {83, 458}, {92, 226}, {184, 436}, {262, 427}, {331, 1446}, {394, 801}, {401, 1968}, {485, 1585}, {486, 1586}, {648, 1993}

▸ Functional Relations10 relations

Notes

Let HaHbHc be the orthic triangle of a triangle ABC, and let

  • O(A) = circle with center A and radius AHa, and define O(B) and O(C) cyclically

  • p(A) = polar of X4 wrt O(A), and define p(B) and p(C) cyclically

  • A″ = p(B)∩p(C), and define B″ and C″ cyclically.

Then A″B″C″ is homothetic to ABC, and the center of homothety is X2052. (Angel Montesdeoca, September 30, 2016)