X850

BARYCENTRIC MULTIPLIER FOR KIEPERT HYPERBOLA

The barycentric product of X850 and the circumcircle is the Kiepert hyperbola.
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 99, 476 }: Central Line L(99, 476) { 2, 647 }: Central Line L(2, 647) { 110, 685 }: Central Line L(110, 685) { 297, 525 }: Central Line L(297, 525) { 316, 512 }: Central Line L(316, 512) { 325, 523 }: Central Line L(325, 523) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_110 = FOCUS OF KIEPERT PARABOLA (0.2516, 0.5478) X_99 = STEINER POINT (0.1109, 0.4322) X_476 = TIXIER POINT (0.9824, 0.2685) X_2 = CENTROID (0.5374, 0.2000) X_647 = CROSSDIFFERENCE OF X(2) AND X(3) (4.2063, -0.5653) X_685 = TRILINEAR POLE OF LINE X(4)X(98) (0.7921, 0.4572) X_297 = -HIRST INVERSE OF X(4) (0.8440, 1.0022) X_525 = ISOGONAL CONJUGATE OF X(112) (-0.0468, 0.2556) X_316 = DROUSSENT PIVOT (-0.7850, -1.9118) X_512 = ISOGONAL CONJUGATE OF X(99) (1.0394, -0.1040) X_325 = -HIRST INVERSE OF X(69) (-0.3370, -0.7398) X_523 = ISOGONAL CONJUGATE OF X(110) (1.0856, -0.0096) X_850 = BARYCENTRIC MULTIPLIER FOR KIEPERT HYPERBOLA (-6.8003, 1.7304) A B C X110 X99 X476 X2 X647 X685 X297 X525 X316 X512 X325 X523 X850 (a, b, c) = (5, 6, 7) | AB = 1

X850 (BARYCENTRIC MULTIPLIER FOR KIEPERT HYPERBOLA) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \((b^{2} - c^{2})/a^{3} : :\)
Barycentrics: \((b^{2} - c^{2})/a^{2} : :\)
Search Value (6, 9, 13): \(18.041819248310\)
▸ Alternate Coordinates2 forms
  • Barycentrics: \(\csc A \sin(B - C) : :\)

  • Barycentrics: \(|AP(1)|^{2} - |AU(1)|^{2} : :\)

▸ Incident Central Lines9 lines

{2, 647}, {99, 476}, {110, 685}, {297, 525}, {316, 512}, {325, 523}, {340, 520}, {669, 804}, {670, 892}

▸ Functional Relations15 relations

Notes

Let P1 and P2 be the two points on the de Longchamps line whose trilinear polars are parallel to the de Longchamps line. P1 and P2 lie on the Kiepert hyperbola and circle {X2, X98, X99}}. X850 is the barycentric product P1*P2. (Randy Hutson, June 7, 2019)