G.21 cut off an equal segment — Heath
I.3
Given two unequal
straight lines, to cut off from the greater a straight line equal to the less.
Let / A B /, C be the two given unequal straight lines, and let / A B / be the greater of them.
Thus it is required to cut off from / A B / the greater a straight line equal to C the less.
At the point A let / A D / be placed equal to the straight line C; [G.20]
and with centre A and distance / A D / let the circle ( D E F ) be described. [G.15]
Now, since the point A is the centre of the circle ( D E F ),
[G.10]/ A E / is
equal to
/ A D /.
But C is also equal to / A D /.
Therefore each of the straight lines / A E /, C is equal to / A D /; so that / A E / is also equal to C. [G.16]
Therefore, given the two straight lines / A B /, C, from / A B / the greater / A E / has been cut off equal to C the less.
(Being) what it was required to do.
Dependency Graph
Required for
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