G.20 transfer a segment to a point — Heath
I.2
Let A be the given point, and / B C / the given straight line.
Thus it is required to place at the point A (as an extremity) a straight line equal to the given straight line / B C /.
From the point A to the point B let the straight line / A B / be joined; [G.14]
and on it let the equilateral triangle < D A B > be constructed. [G.17]
Let the straight lines / A E /, / B F / be produced in a straight line with / D A /, / D B /; [G.18]
with centre B and distance / B C / let the circle ( B C ) be described; [G.15]
and again, with centre D and distance / D G / let the circle ( D G ) be described. [G.15]
Then, since the point B is the centre of the circle ( B C ),
/ B C / is equal to / B G /.
Again, since the point D is the centre of the circle ( D G ),
/ D L / is equal to / D G /.
And in these / D A / is equal to / D B /; therefore the remainder / A L / is equal to the remainder / B G /. [G.19]
But / B C / was also proved equal to / B G /; therefore each of the straight lines / A L /, / B C / is equal to / B G /.
And things which are equal to the same thing are also equal to one another; [G.16]
therefore / A L / is also equal to / B C /.
Therefore at the given point A the straight line / A L / is placed equal to the given straight line / B C /.
(Being) what it was required to do.
Dependency Graph
Required for
G.21, G.25, G.27, G.28, G.29, G.31, G.32, G.34, G.35, G.37, G.39, G.40, G.41, G.42, G.43, G.44, G.45, G.46, G.47, G.48, G.49, G.50, G.51, G.53, G.54, G.56, G.57, G.58, G.59, G.60, G.62, G.64, G.65, G.66, G.67, G.68, G.69, G.70, G.71, G.72, G.73, G.74, G.75, G.79, G.80, G.82, G.83, G.84, G.85, G.87, G.88, G.89, G.90, G.91, G.92, G.93, G.94, G.95, G.97, G.98, G.99, G.100, G.101, G.105, G.106, G.107, G.108, G.110, G.112, G.114, G.116, G.118, G.119, G.120, G.121, G.123, G.124, G.125, G.128, G.129, G.130, G.133, G.134, G.135, G.136, G.137, G.139, G.140, G.141, G.142, G.143, G.144, G.145, G.149, G.151, G.154, G.157, G.158, G.159, G.160, G.161, G.162, G.163, G.164, G.165, G.166, G.167, G.168, G.210, G.211, G.212, G.213, G.214, G.215, G.216, G.218, G.219, G.220, G.221, G.222, G.223, G.225, G.226, G.227, G.228, G.229, G.231, G.232, G.234, G.235, G.236, G.237, G.238, G.239, G.240, G.241, G.243, G.244, G.245, G.246, G.345, G.377, G.378, G.381, G.382, G.383, G.384, G.385, G.386, G.389, G.390, G.393, G.394, G.395, G.396, G.397, G.398, G.399, G.400, G.401, G.402, G.403, G.404, G.405, G.406, G.407, G.408, G.409, G.410, G.411, G.412, G.413, G.414, G.415, G.416, G.417, G.418, G.419, G.420, G.421, G.423, G.425, G.427, G.429, G.431, G.433, G.434, G.435, G.436, G.437, G.438, G.439, G.440, G.441, G.442, G.443, G.444, G.445, G.446, G.447, G.448, G.449, G.450, G.451, G.452, G.453, G.455, G.457, G.458, G.459, G.460, G.461, G.462, G.463, G.464, G.465, G.466, G.467, G.468, G.470, G.472, G.474, G.476, G.477, G.478, G.479, G.480, G.481, G.482, G.483, G.484, G.485, G.486, G.487, G.488, G.489, G.490, G.491, G.492, G.493, G.494, G.495, G.496, G.497, G.498, G.499, G.500, G.501, G.506, G.507, G.508, G.510, G.511, G.512, G.513, G.514, G.517, G.518, G.520, G.522, G.525, G.526, G.527, G.528, G.530, G.531, G.532, G.536, G.538, G.539, G.540, G.541, G.542, G.543, G.544, G.545, G.546, G.547, G.549, G.550, G.551, G.552, G.554, G.555, G.556, G.557, G.558, G.559, G.560, G.563, G.565, G.570, G.571, G.572, G.573, G.574, G.577, G.578, G.579, G.580, G.582, G.583, G.584, G.585, G.586, G.587, G.588, G.589, G.590, G.592, G.594, G.595, G.597, G.600, G.601