Heath ID: I.19
G.28¶
In any triangle the greater angle is subtended by the greater side.
Let ABC be a triangle having the angle ABC greater than the angle BCA;
I say that the side AC is also greater than the side AB.
For, if not, AC is either equal to AB or less.
- Now
ACis not equal toAB; for then the angleABCwould also have been equal to the angleACB; [G.12] but it is not; therefore
ACis not equal toAB.
Neither is AC less than AB, for then the angle ABC would also have been less than the angle ACB; [G.27] but it is not; therefore AC is not less than AB.
And it was proved that it is not equal either. Therefore AC is greater than AB.
Therefore etc.
Q. E. D.
Dependency Graph¶
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"G.25" -> "G.24";
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"G.25" -> "G.7";
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"G.5" -> "G.3";
"G.25" -> "G.3";
"G.8" -> "G.3";
"G.12" -> "G.3";
"G.25" -> "G.17";
"G.19" -> "G.15";
"G.16" -> "G.15";
"G.19" -> "G.5";
"G.8" -> "G.5";
"G.17" -> "G.5";
"G.5" -> "G.1";
"G.24" -> "G.1";
"G.8" -> "G.1";
"G.9" -> "G.1";
"G.5" -> "G.2";
"G.9" -> "G.2";
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"G.14" -> "G.12";
"G.24" -> "G.22";
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"G.21" -> "G.18";
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"G.17" -> "G.11";
"G.12" -> "G.11";
"G.5" -> "G.4";
"G.8" -> "G.4";
"G.9" -> "G.4";
"G.17" -> "G.16";
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