X127

X112-OF-MEDIAL-TRIANGLE

X127 = reflection of X132 in X5
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 132, 5 }: Central Line L(132, 5) { 2, 112 }: Central Line L(2, 112) { 3, 114 }: Central Line L(3, 114) { 113, 141 }: Central Line L(113, 141) { 125, 140 }: Central Line L(125, 140) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_132 = ∩X(4)X(32) (0.5642, 0.5039) X_5 = NINE-POINT CENTER (0.5561, 0.2489) X_2 = CENTROID (0.5374, 0.2000) X_112 = Ψ(ORTHOCENTER, SYMMEDIAN POINT) (0.5162, 0.6121) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_114 = KIEPERT ANTIPODE (0.3616, 0.4140) X_113 = JERABEK ANTIPODE (0.4319, 0.4718) X_141 = COMPLEMENT OF SYMMEDIAN POINT (0.5061, 0.1663) X_125 = CENTER OF JERABEK HYPERBOLA (0.6803, 0.0260) X_140 = MIDPOINT OF X(3) AND X(5) (0.5281, 0.1755) X_127 = -OF-MEDIAL-TRIANGLE (0.5480, -0.0061) A B C X132 X5 X2 X112 X3 X114 X113 X141 X125 X140 X127 (a, b, c) = (5, 6, 7) | AB = 1

X127 (X112-OF-MEDIAL-TRIANGLE) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(bc(\sin 2B - \sin 2C)[(b^{2} - c^{2})\sin 2A - b^{2}\sin 2B + c^{2}\sin 2C] : :\)
Barycentrics: \((\sin 2B - \sin 2C)[(b^{2} - c^{2})\sin 2A - b^{2}\sin 2B + c^{2}\sin 2C] : :\)
Search Value (6, 9, 13): \(4.044284549477\)
▸ Alternate Coordinates1 form
  • Barycentrics: \((b^{2} - c^{2})^{2}(b^{2} + c^{2} - a^{2})(b^{4} + c^{4} - a^{4}) : :\)

X127 lies on the nine-point circle, the cevian circle of X22.

▸ Incident Central Lines7 lines

{2, 112}, {3, 114}, {5, 132}, {113, 141}, {115, 338}, {133, 381}, {125, 140}

▸ Functional Relations17 relations

Notes

Let HaHbHc be the orthic triangle. Let La be the van Aubel line of triangle AHbHc, and define Lb and Lc cyclically. Let A″ = Lb∩Lc, and define B″ and C″ cyclically. The lines HaA″, HbB″, HcC″ concur in X127, which is X3-of-A″B″C″. (Randy Hutson, July 31 2018)