Part II, Chapters IV–V — The Transcendence of π and the Integraph¶
Part II, Chapter IV (§§ 1–7, pp. 68–77) & Chapter V (§§ 1–3, pp. 78–80; Ginn & Co., 1897)
Chapter IV, § 1. Statement of Lindemann’s Theorem for Conjugate Exponents¶
1. Lindemann's proof of the transcendence of $\pi$ (1882) is a direct generalization of Hermite's method (1873). Whereas Hermite proved that $\sum_{k=0}^n C_k e^k = 0$ is impossible for integer exponents $k$, Lindemann replaces each power $e^k$ by a symmetric sum of exponentials over conjugate algebraic numbers:
Lindemann’s Theorem: The number $e$ cannot satisfy an equation with non-zero integer coefficients ($C_0 \neq 0$) of the form
where $k_1, \dots, k_N$ are the roots (real or complex, non-zero) of an algebraic equation with integer coefficients
and likewise $l_1, \dots, l_{N'}$ are the roots of $b l^{N'} + b_1 l^{N'-1} + \dots + b_{N'} = 0$ ($b > 0,\; b_{N'} \neq 0$), and so forth. (In Leibniz's terminology—where $x^\lambda$ for irrational algebraic $\lambda$ was called interscendental—$e$ is not even interscendental, but transcendental of a higher order.)
Because the leading coefficients $a, b, \dots$ need not equal $1$, symmetric functions of $k_1, \dots, k_N$ may be fractions; however, multiplying the roots by $a$ yields the algebraic integers $a k_1, \dots, a k_N$ satisfying the monic integer equation
whose rational symmetric functions are ordinary rational integers.
Chapter IV, §§ 2–3. The Auxiliary Polynomial $\psi(x)$ and Proof of Lindemann’s Theorem¶
2. Retaining Gordan's umbral factorial symbol $h^r = r!$ (1893), we introduce the generalized multiplier $M = \psi(h)$, where
and $p$ is a prime number chosen larger than $|C_0|$, $a, b, \dots$, and $|a_N|, |b_{N'}|, \dots$, eventually tending to $\infty$. The powers of $a, b, \dots$ ensure that in the expansions of both $\psi(h)$ and $\sum_{\nu=1}^N \psi(k_\nu + h)$, every symmetric coefficient numerator is an ordinary integer. Exactly as in Chapter III, $\psi$ satisfies three decisive properties:
$\psi(h)$ is an integer not divisible by $p$: Ordering $\psi(h) = \sum_{r=p-1}^{Np + N'p + \dots + p - 1} c_r h^r$, every numerator $(p - 1)!\,c_r$ is an integer; upon setting $h^r = r!$, all terms for $r \ge p$ contain the prime factor $p$, whereas the leading term ($r = p - 1$) equals
\[(-1)^{p(N + N' + \dots)}\,a_N^p\,b_{N'}^p \cdots a^{(N-1)p + N'p + \dots}\,b^{Np + (N'-1)p + \dots} \not\equiv 0 \pmod p.\]Asymptotic vanishing as $p \to \infty$: For any fixed finite complex argument $x$, writing $\psi(x) = \frac{K^p}{x\cdot (p - 1)!}$ shows that both $\psi(x)$ and $\sum_r |c_r|\,|x|^r$ tend to $0$ as $p \to \infty$.
Every conjugate sum $\sum_{\nu=1}^N \psi(k_\nu + h)$ is an integer divisible by $p$: In $\psi(k_\nu + h)$, the $\nu$-th factor $(k_\nu - k_\nu - h)$ equals $-h$, raising the lowest power of $h$ to $h^p$. Summing across $\nu = 1, \dots, N$ yields symmetric functions of the algebraic integers $a k_\nu, b l_\mu, \dots$:
\[\sum_{\nu=1}^N \psi(k_\nu + h) = \sum_{r=p}^{Np + N'p + \dots + p - 1} C'_r h^r,\]where $(p - 1)!\,C'_r \in \mathbb{Z}$, so replacing $h^r$ by $r!$ ($r \ge p$) leaves an integer divisible by $p$!
3. Now multiply the assumed relation by $\psi(h)$. Because $k_\nu = k' + i k''$ may be complex with modulus $|k_\nu| = \sqrt{k'^2 + k''^2}$, the exponential splitting of Chapter III takes the complex-majorized form
Summing over $r$ and over the conjugate roots $\nu = 1, \dots, N$ decomposes each block into an integer divisible by $p$ plus an arbitrarily small remainder:
The first bracket is an integer congruent to $C_0 \psi(h) \not\equiv 0 \pmod p$ (hence $\ge 1$ in magnitude), whereas for sufficiently large $p$ the second bracket has modulus $< 1$—an impossibility! (Note: if $C_0 = 0$ initially, multiplying by a suitable exponential or shifting exponents reduces to $C_0 \neq 0$.)
Chapter IV, § 4. Lindemann’s Corollary (Arbitrary Algebraic Exponents & Coefficients)¶
4. From Lindemann’s Theorem we deduce immediately a far wider proposition (Lindemann’s Corollary, or the Lindemann–Weierstrass Theorem):
Step A — Unrelated algebraic exponents with integer coefficients: Suppose $C'_0 + C'_1 e^{k_1} + C'_2 e^{l_1} + \dots = 0$ ($C'_i \in \mathbb{Z}$, not all zero) for distinct algebraic numbers $k_1, l_1, \dots$. Forming the Galois product across all conjugate roots $k_\alpha$ ($\alpha = 1, \dots, N$), $l_\beta$ ($\beta = 1, \dots, N'$), etc.,
\[\prod_{\alpha, \beta, \dots} \bigl(C'_0 + C'_1 e^{k_\alpha} + C'_2 e^{l_\beta} + \dots\bigr) = C_0 + C_1\bigl(e^{k_1} + \dots + e^{k_N}\bigr) + C_2\bigl(e^{k_1 + k_2} + \dots\bigr) + \dots,\]collects exponents into symmetric conjugate families satisfying integer equations, which by Lindemann’s Theorem cannot vanish; hence no factor can vanish!
Step B — Arbitrary algebraic coefficients and algebraic exponents: Next suppose $C_0 + C_1 e^k + C_2 e^l + \dots = 0$ where both the exponents $k, l, \dots$ (distinct) and the coefficients $C_0, C_1, C_2, \dots$ (not all zero) are algebraic numbers. Forming the product across all conjugates $C_0^{(\alpha)}, C_1^{(\beta)}, C_2^{(\gamma)}, \dots$ of the coefficients yields a non-trivial exponential polynomial whose coefficients are symmetric functions of algebraic numbers—hence rational numbers, and after clearing denominators, integers—which cannot vanish by Step A!
General Statement of Lindemann’s Corollary: In any non-trivial equation $C_0 + C_1 e^k + C_2 e^l + \dots = 0$ with distinct exponents, the coefficients $C_0, C_1, \dots$ and exponents $k, l, \dots$ cannot all be algebraic numbers.
Chapter IV, §§ 5–7. Transcendence of $\pi$, $y = e^x$, and $y = \arcsin x$¶
5. Transcendence of $\pi$: Consider Euler's equation
Here the coefficients $1, 1$ and the zero exponent in $1 = 1\cdot e^0$ are algebraic; by Lindemann’s Corollary, the exponent $i\pi$ cannot be algebraic. Since $i = \sqrt{-1}$ is algebraic, $\pi$ is a transcendental number!
6. Arithmetic Avoidance of the Exponential Curve $y = e^x$: Excluding the single trivial point $(x = 0, y = 1)$ (where $y - e^x = 0$ collapses to identical zero exponents $1\cdot e^0 - 1\cdot e^0 = 0$), the relation $y - e^x = 0$ (equivalently $x = \ln y$) forbids $x$ and $y$ from being algebraic simultaneously: to every non-zero algebraic $x$ corresponds a transcendental $e^x$, and to every positive algebraic $y \neq 1$ corresponds a transcendental natural logarithm $\ln y$. Geometrically, if we mark all algebraic points $(x, y) \in \overline{\mathbb{Q}}^2$—which cover the plane everywhere densely—the curve $y = e^x$ threads right through them without meeting a single algebraic point except $(0, 1)$!
7. Arithmetic Avoidance of the Sinusoid $y = \arcsin x$: Writing $y = \arcsin x$ in exponential form,
shows similarly that—excluding the origin $(x = 0, y = 0)$—$x$ and $y$ can never be algebraic simultaneously: the curve $y = \arcsin x$ passes through no algebraic point of the plane except $(0, 0)$.
Chapter V, §§ 1–3. The Integraph and the Geometric Construction of $\pi$¶
1. Lindemann’s Theorem settles the ancient quadrature of the circle in the most sweeping sense: not only is $\pi$ unconstructible with straightedge and compasses, there does not even exist any higher algebraic curve $F(x, y) = 0$ with rational coefficients on which $\pi$ occurs as the ordinate for an algebraic abscissa! Any genuine geometric construction of $\pi$ must employ a continuous transcendental apparatus.
2. Precisely such a continuous mechanical instrument is the integraph, invented by the engineer Bruno Abdank-Abakanowicz (Die Integraphen, Teubner, 1889; Les intégraphes, Gauthier-Villars, 1889) and constructed by G. Coradi of Zürich. Given any differential curve $y = f(x)$, as a guiding stylus follows $(x, y)$ along $y = f(x)$, the linkage forms the auxiliary right triangle with vertices $(x, y)$, $(x, 0)$, and $(x - 1, 0)$, whose hypotenuse makes angle $\vartheta$ with the $X$-axis satisfying
A weighted, sharp-edged vertical steering roller is held strictly parallel to this variable hypotenuse so that its contact point $(X, Y)$ on the paper cannot slip sideways and advances with exact slope $\frac{dY}{dX} = y$, tracing the integral curve
in one continuous stroke!
3. Selecting the circle $x^2 + y^2 = r^2$ as differential curve, the integraph traces the multi-branched integral curve
consisting of congruent repeating branches:
Along the $Y$-axis ($X = 0$), the branches cut off the exact ordinates $0,\; \pm\frac{\pi r^2}{2},\; \pm\pi r^2,\; \dots$;
Along the vertical tangents $X = \pm r$, the branches cut off $\pm\frac{\pi r^2}{4},\; \pm\frac{3\pi r^2}{4},\; \dots$.
Setting $r = 1$, the integraph pen traces $\frac{\pi}{4}$, $\frac{\pi}{2}$, and $\pi$ directly, smoothly, and sharply—realizing an actual constructive quadrature of the circle by continuous mechanical motion along the very path envisioned by the ancient inventors of the quadratrix.