X2720

SR(X100, X108)

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 2745, 3 }: Central Line L(2745, 3) { 36, 102 }: Central Line L(36, 102) { 59, 100 }: Central Line L(59, 100) { 108, 513 }: Central Line L(108, 513) { 101, 652 }: Central Line L(101, 652) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_2745 = SR(X(104), X(108)) (0.4623, 0.0742) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_36 = INVERSE-IN-CIRCUMCIRCLE OF INCENTER (1.3333, 1.6330) X_102 = Λ(INCENTER, ORTHOCENTER) (0.6364, -0.3897) X_59 = ISOGONAL CONJUGATE OF X(11) (0.5333, 0.4355) X_100 = ANTICOMPLEMENT OF FEUERBACH POINT (0.1429, 0.4666) X_108 = Ψ(CIRCUMCENTER, INCENTER) (0.5320, 0.6114) X_513 = ISOGONAL CONJUGATE OF X(100) (1.0529, -0.0806) X_101 = Ψ(INCENTER, SYMMEDIAN POINT) (0.2143, 0.5249) X_652 = CROSSDIFFERENCE OF X(1) AND X(4) (7.2558, -0.6836) X_2720 = SR(X(100), X(108)) (0.9103, 0.4054) A B C X2745 X3 X36 X102 X59 X100 X108 X513 X101 X652 X2720 (a, b, c) = (5, 6, 7) | AB = 1

X2720 (SR(X100, X108)) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(a,b,c) : f(b,c,a) : f(c,a,b)\), where f(a,b,c) is as given just before X2677 using P = X100, U = X108
Search Value (6, 9, 13): \(-0.157899240325\)

X2720 lies on the circumcircle.

▸ Incident Central Lines29 lines

{1, 2716}, {3, 2745}, {7, 2861}, {36, 102}, {56, 953}, {57, 2717}, {59, 100}, {65, 2687}, {101, 652}, {103, 2078}, {104, 1319}, {106, 1457}, {108, 513}, {109, 1459}, {497, 2723}, {517, 1395}, {840, 1617}, {883, 2865}, {909, 2272}, {915, 1870}, {919, 2423}, {929, 2401}, {944, 2734}, {972, 1155}, {1214, 2747}, {1397, 2726}, {1402, 2699}, {1420, 2718}, {2283, 2742}

▸ Functional Relations14 relations

Notes

Let A', B', C' be the intersections of line X1X3 and lines BC, CA, AB, resp. The circumcircles of AB'C', BC'A', CA'B' concur in X2720. (Randy Hutson, December 10, 2016)

The tangent lines from X2720 to the incircle intersect the circumcircle in points on the Sherman Line, so forming a poristic triangle with ABC. (Peter Moses, December 3, 2019)