X953

ISOGONAL CONJUGATE OF X952

For a construction of X953 involving the Euler line and X110, see Antreas Hatzipolakis and César Lozada, Hyacinthos 26050.
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 901, 3 }: Central Line L(901, 3) { 36, 109 }: Central Line L(36, 109) { 100, 517 }: Central Line L(100, 517) { 104, 513 }: Central Line L(104, 513) { 110, 859 }: Central Line L(110, 859) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_901 = ISOGONAL CONJUGATE OF X(900) (1.0000, -0.0000) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_36 = INVERSE-IN-CIRCUMCIRCLE OF INCENTER (1.3333, 1.6330) X_109 = Ψ(INCENTER, CIRCUMCENTER) (0.3636, 0.5938) X_100 = ANTICOMPLEMENT OF FEUERBACH POINT (0.1429, 0.4666) X_517 = ISOGONAL CONJUGATE OF X(104) (0.8180, 0.7154) X_104 = ANTIPODE OF X(100) (0.8571, -0.2624) X_513 = ISOGONAL CONJUGATE OF X(100) (1.0529, -0.0806) X_110 = FOCUS OF KIEPERT PARABOLA (0.2516, 0.5478) X_859 = INTERCEPT OF EULER LINE AND TRILINEAR POLAR OF X(81) (1.1279, 1.7448) X_953 = ISOGONAL CONJUGATE OF X(952) (0.0000, 0.2041) A B C X901 X3 X36 X109 X100 X517 X104 X513 X110 X859 X953 (a, b, c) = (5, 6, 7) | AB = 1

X953 (ISOGONAL CONJUGATE OF X952) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(a/[2a^{4} - 2a^{3}(b + c) - a^{2}(b^{2} - 4bc + c^{2}) + (2a - b - c)(b - c)(b^{2} - c^{2})] : :\)
Search Value (6, 9, 13): \(14.014257686059\)

X953 lies on the circumcircle.

▸ Incident Central Lines5 lines

{3, 901}, {36, 109}, {100, 517}, {104, 513}, {110, 859}

▸ Functional Relations12 relations

Notes

Let L be the line tangent to the incircle and the nine-point circle; i.e., the line X11X244, called the Feuerbach tangent line. Let LA be the reflection of L in BC, and define LB and LC cyclically. Let A″ = LB∩LC, and define B″ and C″ cyclically. The lines AA″, BB″, CC″ concur in X953. (Randy Hutson, 9/23/2011)