X823

ISOGONAL CONJUGATE OF X822

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 100, 107 }: Central Line L(100, 107) { 264, 379 }: Central Line L(264, 379) { 110, 681 }: Central Line L(110, 681) { 648, 651 }: Central Line L(648, 651) { 662, 811 }: Central Line L(662, 811) { 774, 821 }: Central Line L(774, 821) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_822 = CROSSDIFFERENCE OF X(1) AND X(29) (6.5481, -0.2984) X_100 = ANTICOMPLEMENT OF FEUERBACH POINT (0.1429, 0.4666) X_107 = Ψ(SYMMEDIAN POINT, ORTHOCENTER) (0.5733, 0.6071) X_264 = ISOTOMIC CONJUGATE OF CIRCUMCENTER (0.5720, 0.3293) X_379 = EULER LINE INTERCEPT OF LINE X(6)X(7) (0.5733, 0.2937) X_110 = FOCUS OF KIEPERT PARABOLA (0.2516, 0.5478) X_681 = TRILINEAR POLE OF LINE X(6)X(158) (0.5783, 0.6063) X_648 = TRILINEAR POLE OF EULER LINE (0.4563, 0.5855) X_651 = TRILINEAR POLE OF LINE X(1)X(3) (0.3048, 0.5599) X_662 = TRILINEAR POLE OF LINE X(1)X(21) (0.1811, 0.4951) X_811 = ISOGONAL CONJUGATE OF X(810) (0.4151, 0.5616) X_774 = CROSSPOINT OF X(1) AND X(158) (0.6363, 0.3186) X_821 = ISOGONAL CONJUGATE OF X(820) (0.5996, 0.4597) X_823 = ISOGONAL CONJUGATE OF X(822) (0.5623, 0.6035) A B C X822 X100 X107 X264 X379 X110 X681 X648 X651 X662 X811 X774 X821 X823 (a, b, c) = (5, 6, 7) | AB = 1

X823 (ISOGONAL CONJUGATE OF X822) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(1/(\sec^{2} B - \sec^{2} C) : :\)
Search Value (6, 9, 13): \(0.526843354611\)
▸ Alternate Coordinates3 forms
  • Trilinears: \(1/(\csc B/2 - \csc C/2) : :\)

  • Trilinears: \(1/(\csc 2B - \csc 2C) : :\)

  • Trilinears: \(b^{2}c^{2}/[(b^{2} - c^{2})(b^{2} + c^{2} - a^{2})^{2}] : :\)

▸ Incident Central Lines7 lines

{100, 107}, {110, 681}, {158, 897}, {264, 379}, {648, 651}, {662, 811}, {774, 821}

▸ Functional Relations9 relations

Notes

Let La be the A-extraversion of line X1X29, and define Lb, Lc cyclically. Let A' = Lb ∩ Lc, and define B' and C' cyclically. The lines AA', BB', CC' concur in X823. (Randy Hutson, January 29, 2018)