X510

8th ISOSCELIZER POINT

The isoscelizer equations
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_510 = 8th ISOSCELIZER POINT (0.4829, 0.1227) A B C X510 (a, b, c) = (5, 6, 7) | AB = 1

X510 (8th ISOSCELIZER POINT) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Trilinears: \(b^{3/2} + c^{3/2} - a^{3/2} : :\)
Search Value (6, 9, 13): \(4.676414624511\)

Notes

[area of T(A,X)]/\(a^{2}\) = [area of T(B,X)]/\(b^{2}\) = [area of T(C,X)]/\(c^{2}\)

have solution X = X510. (Peter Yff, 4/9/99)