X509

7th ISOSCELIZER POINT

The isoscelizer equations
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_509 = 7th ISOSCELIZER POINT (0.5951, 0.2721) A B C X509 (a, b, c) = (5, 6, 7) | AB = 1

X509 (7th ISOSCELIZER POINT) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Trilinears: \((\tan A/2)^{1/2} : :\)
Search Value (6, 9, 13): \(0.873967847906\)
▸ Alternate Coordinates1 form

  • Trilinears: 1/(semi-minor axis of A-Soddy ellipse) : :

▸ Functional Relations1 relation

  • X509 = trilinear square root of X57

Notes

[area of T(A,X)]/a = [area of T(B,X)]/b = [area of T(C,X)]/c

have solution X = X509. (Peter Yff, 4/9/99)