X508

6th ISOSCELIZER POINT

The isoscelizer equations
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_508 = 6th ISOSCELIZER POINT (0.5662, 0.2377) A B C X508 (a, b, c) = (5, 6, 7) | AB = 1

X508 (6th ISOSCELIZER POINT) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Trilinears: \(a^{-1/2}\sec(A/2) : b^{-1/2}\sec(B/2) : c^{-1/2}\sec(C/2)\)
Barycentrics: \(a^{1/2}\sec(A/2) : b^{1/2}\sec(B/2) : c^{1/2}\sec(C/2)\)
Search Value (6, 9, 13): \(1.548710508717\)
▸ Functional Relations3 relations

Notes

a[area of T(A,X)] = b[area of T(B,X)] = c[area of T(C,X)]

have solution X = X508. (Peter Yff, 4/9/99)