X507

5th ISOSCELIZER POINT

The isoscelizer equations
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_507 = 5th ISOSCELIZER POINT (0.5765, 0.2440) A B C X507 (a, b, c) = (5, 6, 7) | AB = 1

X507 (5th ISOSCELIZER POINT) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Trilinears: \(f(A,B,C) : f(B,C,A) : f(C,A,B)\), where \(f(A,B,C) = (\cos A/2)^{-1/2}\)
Barycentrics: \(af(A,B,C) : bf(B,C,A) : cf(C,A,B)\)
Search Value (6, 9, 13): \(1.426982771047\)
▸ Functional Relations1 relation

Notes

\([\operatorname{area} of T(A,X)][X(A)]^{2} = [\operatorname{area} of T(B,X)][X(B)]^{2} = [\operatorname{area} of T(C,X)][X(C)]^{2}\)

have solution X = X507. (Peter Yff, 4/9/99)