X114

KIEPERT ANTIPODE

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) circumcircle: Circumcircle of △ABC { 5, 39 }: Central Line L(5, 39) { 2, 98 }: Central Line L(2, 98) { 4, 99 }: Central Line L(4, 99) { 3, 127 }: Central Line L(3, 127) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_5 = NINE-POINT CENTER (0.5561, 0.2489) X_39 = BROCARD MIDPOINT (0.5778, 0.2305) X_2 = CENTROID (0.5374, 0.2000) X_98 = TARRY POINT (0.8891, -0.2281) X_4 = ORTHOCENTER (0.6122, 0.3958) X_99 = STEINER POINT (0.1109, 0.4322) X_127 = -OF-MEDIAL-TRIANGLE (0.5480, -0.0061) X_114 = KIEPERT ANTIPODE (0.3616, 0.4140) A B C X3 X5 X39 X2 X98 X4 X99 X127 X114 (a, b, c) = (5, 6, 7) | AB = 1

X114 (KIEPERT ANTIPODE) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

  • Circle: Circumcircle (circumcircle) — Passes through vertices A, B, C; centered at X3 CIRCUMCENTER

  • Related Centers: X3 (CIRCUMCENTER)

Trilinears: \(bc[b \sec(B + \omega ) + c \sec(C + \omega )] : :\)
Barycentrics: \(b \sec(B + \omega ) + c \sec(C + \omega ) : :\)
Search Value (6, 9, 13): \(-1.118944978639\)
▸ Alternate Coordinates2 forms
  • Trilinears: \(\cos(B - C) \cos 2\omega - \sin \omega \sin(A + \omega )\) (Peter J. C. Moses, 9/12/03)

  • Barycentrics: \((b^{4} + c^{4} - a^{2}b^{2} - a^{2}c^{2})(2a^{4} + b^{4} + c^{4} - a^{2}b^{2} - a^{2}c^{2} - 2b^{2}c^{2}) : :\)

X114 lies on the bicevian conic of X2 and X99.

▸ Incident Central Lines11 lines

{2, 98}, {3, 127}, {4, 99}, {5, 39}, {25, 135}, {52, 211}, {113, 690}, {132, 684}, {136, 427}, {325, 511}, {381, 543}

▸ Functional Relations24 relations

Notes

Let HaHbHc be the orthic triangle. Let La be the Lemoine axis of triangle AHbHc, and define Lb and Lc cyclically. Let A″ = Lb∩Lc, and define B″ and C″ cyclically. Triangle A″B″C″ is inversely similar to ABC, with similicenter X2. The lines HaA″, HbB″, HcC″ concur in X114, which is X3-of-A″B″C″.

Let OA be the circle centered at the A-vertex of the obverse triangle of X69 and passing through A; define OB and OC cyclically. X114 is the radical center of OA, OB, OC. (Randy Hutson, August 30, 2020)