X3563

1st MOSES CIRCUMCIRCLE POINT

X3563 = reflection of X3565 in X3
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 3565, 3 }: Central Line L(3565, 3) { 4, 99 }: Central Line L(4, 99) { 25, 110 }: Central Line L(25, 110) { 24, 112 }: Central Line L(24, 112) { 2, 136 }: Central Line L(2, 136) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_3565 = 2nd MOSES CIRCUMCIRCLE POINT (0.0672, -0.1683) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_4 = ORTHOCENTER (0.6122, 0.3958) X_99 = STEINER POINT (0.1109, 0.4322) X_25 = HOMOTHETIC CENTER OF ORTHIC AND TANGENTIAL TRIANGLES (0.6329, 0.4497) X_110 = FOCUS OF KIEPERT PARABOLA (0.2516, 0.5478) X_24 = PERSPECTOR OF ABC AND ORTHIC-OF-ORTHIC TRIANGLE (0.6627, 0.5278) X_112 = Ψ(ORTHOCENTER, SYMMEDIAN POINT) (0.5162, 0.6121) X_2 = CENTROID (0.5374, 0.2000) X_136 = INTERSECTION OF LINE X(4)X(110) AND X(25)X(132) (0.8024, 0.3155) X_3563 = 1st MOSES CIRCUMCIRCLE POINT (0.9328, 0.3724) A B C X3565 X3 X4 X99 X25 X110 X24 X112 X2 X136 X3563 (a, b, c) = (5, 6, 7) | AB = 1

X3563 (1st MOSES CIRCUMCIRCLE POINT) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \((\sec A)/(b^{2} \cos^{2} C + c^{2} \cos^{2} B - bc \cos A) : :\)
Search Value (6, 9, 13): \(11.115434509251\)
▸ Alternate Coordinates1 form
  • Trilinears: \(a/[(b^{2} + c^{2} - a^{2})(2a^{4} + b^{4} + c^{4} - 2b^{2}c^{2} - c^{2} a^{2} - a^{2}b^{2})] : :\)

X3563 lies on the circumcircle.

▸ Incident Central Lines15 lines

{2, 136}, {3, 2971}, {4, 99}, {24, 112}, {25, 110}, {100, 1824}, {101, 2333}, {107, 459}, {186, 691}, {232, 1692}, {378, 1296}, {403, 935}, {427, 930}, {468, 476}, {934, 1426}

▸ Functional Relations15 relations

Notes

The antipodal pair X3563 to X3565 were described by Peter Moses, Dec. 13, 2004.

Let A' be the reflection in line BC of the A-vertex of the antipedal triangle of X6, and define B' and C' cyclically. Let OA be the circumcenter of AB'C', and define OB and OC cyclically. Let U be the circumcenter of A'BC, and define V and W cyclically. Let O' be the circumcenter of OAOBOC. Let O″ be the circumcenter of UVW. Then X3563 = Λ(O',O″). Also, O'O″∩(infinity line) = X3564. (Randy Hutson, June 19, 2015)