G.34 construct a perpendicular at a point on a line — Heath
I.11
Let / A B / be the given straight line, and C the given point on it.
Thus it is required to draw from the point C a straight line at right angles to the straight line / A B /.
Let a point D be taken at random on / A C /; let / C E / be made equal to / C D /; [G.21]
on / D E / let the equilateral triangle < F D E > be constructed, [G.17]
and let / F C / be joined; [G.14]
I say that the straight line / F C / has been drawn at right angles to the given straight line / A B / from C the given point on it.
For, since / D C / is equal to / C E /, and / C F / is common,
the two sides / D C /, / C F / are equal to the two sides / E C /, / C F / respectively;
and the base / D F / is equal to the base / F E /;
[G.29]therefore the
angle < D C F ) is
equal to the angle
< E C F );
and they are adjacent angles.
But, when a straight line set up on a straight line makes the adjacent angles equal to one another, each of the equal angles is right; [G.33]
therefore each of the angles < D C F ), < F C E ) is right.
Therefore the straight line / C F / has been drawn at right angles to the given straight line / A B / from the given point C on it.
Dependency Graph
Required for
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