Commentary on Proposition X.51¶
Back to Proposition X.51.
Take numbers $m$, $n$ such that $(m + n)$ has not to either $m$ or $n$ the ratio of square to square.
Take $x$ such that
$$(m + n) : m = k^2 p^2 : x^2,$$
whence
$$x = kp \sqrt{\frac{m}{m + n}} = \frac{kp}{\sqrt{1 + \lambda}}\text{, say.}$$
Then $kp + x$, or $kp + \frac{kp}{\sqrt{1 + \lambda}}$, is a fourth binomial straight line.
For $\sqrt{k^2 p^2 - x^2}$ is incommensurable in length with $kp$, and $kp$ is commensurable in length with $p$.
The corresponding fourth apotome [x. 88] is
$$kp - \frac{kp}{\sqrt{1 + \lambda}}.$$
The equation of which the two expressions are the roots is
$$x^2 - 2kp \cdot x + \frac{\lambda}{1 + \lambda} k^2 p^2 = 0,$$
or
$$x^2 - 2ax + \frac{\lambda}{1 + \lambda} a^2 = 0,$$
where
$$a = kp.$$