PROPOSITION 20.

Prime numbers are more than any assigned multitude of prime numbers.

Let A, B, C be the assigned prime numbers ;

I say that there are more prime numbers than A, B, C.

For let the least number measured by A, B, C be taken, and let it be DE ; let the unit DF be added to DE.

A B C G E D F

Then EF is either prime or not.

First, let it be prime ;

then the prime numbers A, B, C, EF have been found which are more than A, B, C.

Next, let EF not be prime ;

[VII. 31]therefore it is measured by some prime number.

Let it be measured by the prime number G.

I say that G is not the same with any of the numbers A, B, C.

For, if possible, let it be so.

Now A, B, C measure DE ;
therefore G also will measure DE.
But it also measures EF.
Therefore G, being a number, will measure the remainder, the unit DF : which is absurd.
Therefore G is not the same with any one of the numbers A, B, C.
And by hypothesis it is prime.
Therefore the prime numbers A, B, C, G have been found which are more than the assigned multitude of A, B, C.
Q. E. D.

Dependency Graph

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See Commentary on Proposition IX.20.