PROPOSITION 22.¶
Let the three given straight lines be A, B, C, and of these let two taken together in any manner be greater than the remaining one, namely,
thus it is required to construct a triangle out of straight lines equal to A, B, C.
Let there be set out a straight line DE, terminated at D but of infinite length in the direction of E, and let DF be made equal to A, FG equal to B, and GH equal to C. [I. 3]
With centre F and distance FD let the circle DKL be described;
again, with centre G and distance GH let the circle KLH be described;
and let KF, KG be joined;
I say that the triangle KFG has been constructed out of three straight lines equal to A, B, C.
For, since the point F is the centre of the circle DKL,
But FD is equal to A;
Again, since the point G is the centre of the circle LKH,
But GH is equal to C;
And FG is also equal to B;
Therefore out of the three straight lines KF, FG, GK, which are equal to the three given straight lines A, B, C, the triangle KFG has been constructed.
See Commentary on Proposition I.22.