X3602

ISOGONAL CONJUGATE OF X3274

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 356, 357 }: Central Line L(356, 357) { 1134, 1137 }: Central Line L(1134, 1137) { 1135, 1136 }: Central Line L(1135, 1136) { 3274, 3604 }: Central Line L(3274, 3604) { 3275, 3603 }: Central Line L(3275, 3603) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_3274 = PERSPECTOR OF TRIANGLES P1P2P3 AND J1J2J3 (0.5554, 0.2055) X_356 = MORLEY CENTER (0.5727, 0.2361) X_357 = 1st MORLEY-TAYLOR-MARR CENTER (0.5757, 0.2422) X_1134 = 3rd MORLEY-TAYLOR-MARR CENTER (0.5584, 0.2154) X_1137 = 6th MORLEY-TAYLOR-MARR CENTER (0.4890, 0.0964) X_1135 = 4th MORLEY-TAYLOR-MARR CENTER (0.5834, 0.2515) X_1136 = 5th MORLEY-TAYLOR-MARR CENTER (0.6158, 0.4039) X_3604 = ISOGONAL CONJUGATE OF X(3273) (0.5684, 0.2299) X_3275 = PERSPECTOR OF TRIANGLES S1S2S3 AND J1J2J3 (0.6086, 0.2928) X_3603 = ISOGONAL CONJUGATE OF X(3275) (0.5222, 0.1769) X_3602 = ISOGONAL CONJUGATE OF X(3274) (0.5856, 0.2621) A B C X3274 X356 X357 X1134 X1137 X1135 X1136 X3604 X3275 X3603 X3602 (a, b, c) = (5, 6, 7) | AB = 1

X3602 (ISOGONAL CONJUGATE OF X3274) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(\csc(A/3 - \pi /3) : \csc(B/3 - \pi /3) : \csc(C/3 - \pi /3)\)
Barycentrics: \((\sin A)\csc(A/3 - \pi /3) : (\sin B)\csc(B/3 - \pi /3) : (\sin C)\csc(C/3 - \pi /3)\)
Search Value (6, 9, 13): \(1.051343278177\)
▸ Alternate Coordinates1 form
  • Trilinears: \(\cos(A/3) - 2 \cos(B/3) \cos(C/3) : \cos(B/3) - 2 \cos(C/3) \cos(A/3) : \cos(C/3) - 2 \cos(A/3) \cos(B/3)\) (Bernard Gibert, January 10, 2013)

▸ Incident Central Lines5 lines

{356, 357}, {1134, 1137}, {1135, 1136}, {3274, 3604}, {3275, 3603}

▸ Functional Relations2 relations

Notes

Let A'B'C' be the 1st Morley triangle. Let A″ be the trilinear pole of line B'C', and define B″ and C″ cyclically. The lines AA″, BB″, CC″ concur in X3602. (Randy Hutson, July 11, 2019)

Let A'B'C' be the 1st Morley triangle. Let A* be the foot of the perpendicular from A to line B'C', and define B* and C* cyclically. The lines A'A*, B'B*, C'C* concur in X3602. (Randy Hutson, July 11, 2019)

Let A'B'C' be the 2nd Morley triangle. Let Ba and Ca be points on BC such that A'BcCa is an equilateral triangle; define Cb and Ac cyclically, and define Ab and Bc cyclically. Let A″ be the midpoint of Ab and Ac, and define B″ and C″ cyclically. Then A″B″C″, here named the 2nd MORLEY-MIDPOINT TRIANGLE, is an equilateral triangle that is homothetic to A'B'C' and perspective to ABC, with perspector X3602. (Thanh Oai Dao and Peter Moses, March 30, 2018)