X3272

CENTER OF EQUILATERAL TRIANGLE J1J2J3

Let A1B1C1, A2B2C2, A3B3C3 be the 1st Morley, 2nd Morley and 3rd Morley triangles of ABC, respectively. Then {A, A1, A2, A3} are concyclic on a circle, A0.
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 396, 523 }: Central Line L(396, 523) { 357, 1135 }: Central Line L(357, 1135) { 358, 1136 }: Central Line L(358, 1136) { 1134, 1137 }: Central Line L(1134, 1137) { 3, 3334 }: Central Line L(3, 3334) { 356, 3273 }: Central Line L(356, 3273) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_396 = MIDPOINT OF X(13) AND X(15) (0.5699, 0.2349) X_523 = ISOGONAL CONJUGATE OF X(110) (1.0856, -0.0096) X_357 = 1st MORLEY-TAYLOR-MARR CENTER (0.5757, 0.2422) X_1135 = 4th MORLEY-TAYLOR-MARR CENTER (0.5834, 0.2515) X_358 = 2nd MORLEY-TAYLOR-MARR CENTER (0.5670, 0.2245) X_1136 = 5th MORLEY-TAYLOR-MARR CENTER (0.6158, 0.4039) X_1134 = 3rd MORLEY-TAYLOR-MARR CENTER (0.5584, 0.2154) X_1137 = 6th MORLEY-TAYLOR-MARR CENTER (0.4890, 0.0964) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_3334 = PERSPECTOR OF TRIANGLES T1T2T3 AND J1J2J3 (0.5478, 0.1930) X_356 = MORLEY CENTER (0.5727, 0.2361) X_3273 = PERSPECTOR OF TRIANGLES M1M2M3 AND J1J2J3 (0.5744, 0.2367) X_3272 = CENTER OF EQUILATERAL TRIANGLE J1J2J3 (0.5698, 0.2349) A B C X396 X523 X357 X1135 X358 X1136 X1134 X1137 X3 X3334 X356 X3273 X3272 (a, b, c) = (5, 6, 7) | AB = 1

X3272 (CENTER OF EQUILATERAL TRIANGLE J1J2J3) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(\cos(B/3 - C/3) : :\)
Search Value (6, 9, 13): \(1.622283534100\)
▸ Alternate Coordinates1 form
  • Trilinears: \(\cos(B/3) \cos(C/3) + \sin(B/3) \sin(C/3) : :\)

▸ Incident Central Lines8 lines

{3, 3334}, {356, 3273}, {357, 1135}, {358, 1136}, {396, 523}, {1134, 1137}, {3274, 3276}, {3275, 3277}

▸ Functional Relations1 relation

Notes

{B, B1, B2, B3} are concyclic on a circle, B0.

{C, C1, C2, C3} are concyclic on a circle C0.

The radical center of A0, B0, C0 is X3272. (César Lozada, June 16, 2018)