X1491

CROSSDIFFERENCE OF X1 AND X32

X1491 = reflection of X659 in X650
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 659, 650 }: Central Line L(659, 650) { 10, 514 }: Central Line L(10, 514) { 44, 513 }: Central Line L(44, 513) { 325, 523 }: Central Line L(325, 523) { 667, 830 }: Central Line L(667, 830) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_659 = CROSSDIFFERENCE OF X(1) AND X(39) (1.9286, 2.2162) X_650 = CROSSDIFFERENCE OF X(1) AND X(3) (13.7143, -4.1991) X_10 = SPIEKER CENTER (0.5204, 0.1833) X_514 = ISOGONAL CONJUGATE OF X(101) (1.0761, -0.0329) X_44 = -LINE CONJUGATE OF X(1) (2.1429, 2.0996) X_513 = ISOGONAL CONJUGATE OF X(100) (1.0529, -0.0806) X_325 = -HIRST INVERSE OF X(69) (-0.3370, -0.7398) X_523 = ISOGONAL CONJUGATE OF X(110) (1.0856, -0.0096) X_667 = CROSSDIFFERENCE OF X(2) AND X(37) (-6.1667, 5.7155) X_830 = ODD (1, 3) INFINITY POINT (1.0590, -0.0690) X_1491 = CROSSDIFFERENCE OF X(1) AND X(32) (25.5000, -10.6145) A B C X659 X650 X10 X514 X44 X513 X325 X523 X667 X830 X1491 (a, b, c) = (5, 6, 7) | AB = 1

X1491 (CROSSDIFFERENCE OF X1 AND X32) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(b^{3} - c^{3} : :\)
Search Value (6, 9, 13): \(-29.540153474797\)
▸ Incident Central Lines5 lines

{10, 514}, {44, 513}, {325, 523}, {663, 1193}, {667, 830}

▸ Functional Relations8 relations

Notes

Let L be the line PU(10) = X10X514; let M be the trilinear polar of the cevapoint of PU(10), so that M = X522X1491. Let V = P(10)-Ceva conjugate of U(10) and let W = U(10)-Ceva conjugate of P(10). The lines L, M, and VW concur in X1491. (Randy Hutson, December 26, 2015)