X1001

MIDPOINT OF X1 AND X9

Let A* be the tangency point of OA and the circumcircle, and define B* and C* cyclically. Let A** be the radical trace of OB and OC. The lines A*A**, B*B**, C*C** concur in X1001.
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 1, 9 }: Incenter–Symmedian Line { 1, 6 }: Incenter–Symmedian Line { 2, 11 }: Central Line L(2, 11) { 7, 21 }: Central Line L(7, 21) { 3, 142 }: Central Line L(3, 142) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_1 = INCENTER (0.5714, 0.2333) X_9 = MITTENPUNKT (0.5110, 0.1615) X_6 = SYMMEDIAN POINT (LEMOINE POINT, GREBE POINT) (0.6000, 0.2672) X_2 = CENTROID (0.5374, 0.2000) X_11 = FEUERBACH POINT (0.7347, 0.0667) X_7 = GERGONNE POINT (0.5903, 0.2769) X_21 = SCHIFFLER POINT (0.5287, 0.1771) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_142 = COMPLEMENT OF X(9) (0.5506, 0.2192) X_1001 = MIDPOINT OF X(1) AND X(9) (0.5412, 0.1974) A B C X1 X9 X6 X2 X11 X7 X21 X3 X142 X1001 (a, b, c) = (5, 6, 7) | AB = 1

X1001 (MIDPOINT OF X1 AND X9) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(a^{2} - a(b + c) - 2bc : :\)
Search Value (6, 9, 13): \(2.631140604343\)
▸ Linear Combinations1 combination
▸ Incident Central Lines17 lines

{1, 6}, {2, 11}, {3, 142}, {7, 21}, {8, 344}, {31, 940}, {35, 474}, {42, 748}, {63, 354}, {182, 692}, {388, 452}, {527, 551}, {529, 1056}, {614, 968}, {750, 902}, {846, 982}, {943, 1058}

▸ Functional Relations12 relations

Notes

Let OA be the circle tangent of side BC at its midpoint and to the circumcircle on the side of BC opposite A. Define OB and OC cyclically. X1001 is the radical center of the circles OA, OB, OC. (Randy Hutson, 9/23/2011)

Let LA and MA be the external tangents to circles OB and OC, with LA being the farther from OA. Define LB, LC, MB, and MC cyclically. Let A' = LB∩LC and A″ = MB∩MC, and define B', B″, C', and C″ cyclically. The lines A'A″, B'B″, C'C″ concur in X1001.

For details and relationships among X1001, X1, X145, X3361, X3616, X3913, and X4719, see

Luis González, “On a Triad of Circles Tangent to the Circumcircle and the Sides at Their Midpoints,” Forum Geometricorum 11 (2011) 145-154.

Let A' be the line through X1 parallel to line BC. Let AB = A'∩AB and AC = A'∩AC. Define BC and CA cyclically, and define BA and CB cyclically. The six points AB, BC, CA, AB, BC, CA lie on a conic whose center is X1001. (Angel Montesdeoca, April 27, 2016)

X1001 is the {X1,X238}-harmonic conjugate of X6.