X901

ISOGONAL CONJUGATE OF X900

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 953, 3 }: Central Line L(953, 3) { 36, 106 }: Central Line L(36, 106) { 59, 109 }: Central Line L(59, 109) { 88, 105 }: Central Line L(88, 105) { 100, 513 }: Central Line L(100, 513) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_953 = ISOGONAL CONJUGATE OF X(952) (0.0000, 0.2041) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_36 = INVERSE-IN-CIRCUMCIRCLE OF INCENTER (1.3333, 1.6330) X_106 = Λ(INCENTER, CENTROID) (1.0000, 0.0000) X_59 = ISOGONAL CONJUGATE OF X(11) (0.5333, 0.4355) X_109 = Ψ(INCENTER, CIRCUMCENTER) (0.3636, 0.5938) X_88 = ISOGONAL CONJUGATE OF X(44) (1.0000, 0.0000) X_105 = Λ(INCENTER, SYMMEDIAN POINT) (0.9714, -0.0933) X_100 = ANTICOMPLEMENT OF FEUERBACH POINT (0.1429, 0.4666) X_513 = ISOGONAL CONJUGATE OF X(100) (1.0529, -0.0806) X_901 = ISOGONAL CONJUGATE OF X(900) (1.0000, -0.0000) A B C X953 X3 X36 X106 X59 X109 X88 X105 X100 X513 X901 (a, b, c) = (5, 6, 7) | AB = 1

X901 (ISOGONAL CONJUGATE OF X900) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(a/[(b - c)(b + c - 2a)] : :\)
Search Value (6, 9, 13): \(-0.449531897666\)

X901 lies on the circumcircle.

▸ Incident Central Lines11 lines

{3, 953}, {6, 2384}, {36, 106}, {55, 840}, {59, 109}, {88, 105}, {100, 513}, {101, 649}, {104, 517}, {484, 759}, {675, 903}

▸ Functional Relations21 relations

Notes

Let LA be the line of reflection of line X1X5 in line BC, and define LB and LC cyclically. Let A' = LB∩LC, and define B' and C' cyclically. The lines AA', BB', CC' concur in X901. (Randy Hutson, 9/23/2011)

Let La, Lb, Lc be the lines through A, B, C, resp. parallel to the antiorthic axis. Let Ma, Mb, Mc be the reflections of BC, CA, AB in La, Lb, Lc, resp. Let A' = Mb∩Mc, and define B' and C' cyclically. Triangle A'B'C' is inversely similar to, and 3 times the size of, ABC. The centroid of A'B'C' is X901; see Hyacinthos #16741/16782, Sep 2008. (Randy Hutson, March 25, 2016)

Let A', B', C' be the intersections of the Nagel line and lines BC, CA, AB, resp. The circumcircles of AB'C', BC'A', CA'B' concur in X901. (Randy Hutson, March 25, 2016)