X628

ANTICOMPLEMENT OF X18

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 18, 630 }: Central Line L(18, 630) { 2, 18 }: Central Line L(2, 18) { 54, 69 }: Central Line L(54, 69) { 3, 299 }: Central Line L(3, 299) { 5, 303 }: Central Line L(5, 303) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_18 = 2nd NAPOLEON POINT (0.4434, 0.1317) X_630 = COMPLEMENT OF X(18) (0.5844, 0.2341) X_2 = CENTROID (0.5374, 0.2000) X_54 = KOSNITA POINT (0.5880, 0.2176) X_69 = SYMMEDIAN POINT OF THE ANTICOMPLEMENTARY TRIANGLE (0.4122, 0.0654) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_299 = ISOTOMIC CONJUGATE OF 2nd ISOGONIC CENTER (-1.1465, -1.6097) X_5 = NINE-POINT CENTER (0.5561, 0.2489) X_303 = ISOTOMIC CONJUGATE OF 2nd NAPOLEON POINT (0.6079, 0.2757) X_628 = ANTICOMPLEMENT OF X(18) (0.7255, 0.3365) A B C X18 X630 X2 X54 X69 X3 X299 X5 X303 X628 (a, b, c) = (5, 6, 7) | AB = 1

X628 (ANTICOMPLEMENT OF X18) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(a,b,c) : f(b,c,a) : f(c,a,b)\), where \(f(a,b,c) = [S_{B}S_{C} + 2S_{A}(a^{2} - \sqrt{3} \operatorname{area})]/a\)
Barycentrics: \(g(a,b,c) : g(b,c,a) : g(c,a,b)\), where \(g(a,b,c) = af(a,b,c)\)
Search Value (6, 9, 13): \(40.449454373023\)
▸ Alternate Coordinates1 form
  • Trilinears: \(F(18)/a + 2 \sec(A + \pi /3) : F(18)/b + 2 \sec(B + \pi /3) : F(18)/c + 2 \sec(C + \pi /3)\)

X628 lies on the Napoleon cubic.

▸ Incident Central Lines9 lines

{2, 18}, {3, 299}, {4, 617}, {5, 303}, {15, 636}, {20, 622}, {54, 69}, {62, 619}, {140, 298}

▸ Functional Relations7 relations

Notes

Erect equilateral triangles inwards on the sides of triangle ABC; the circumcenter of the apices is X628. (Peter Moses, 7/16,2003)

Let A' be the isogonal conjugate of the A-vertex of the outer Napoleon triangle, and define B' and C' cyclically. Triangle A'B'C' is perspective to the outer Napoleon triangle at X5, and to the inner Napoleon triangle at X628. (Randy Hutson, June 7, 2019)

Let OA be the circle centered at the A-vertex of the inner Fermat triangle and passing through A; define OB and OC cyclically. X628 is the radical center of OA, OB, OC. (Randy Hutson, August 30, 2020)