X627

ANTICOMPLEMENT OF X17

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 17, 629 }: Central Line L(17, 629) { 2, 17 }: Central Line L(2, 17) { 54, 69 }: Central Line L(54, 69) { 3, 298 }: Central Line L(3, 298) { 5, 302 }: Central Line L(5, 302) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_17 = 1st NAPOLEON POINT (0.5666, 0.2383) X_629 = COMPLEMENT OF X(17) (0.5228, 0.1808) X_2 = CENTROID (0.5374, 0.2000) X_54 = KOSNITA POINT (0.5880, 0.2176) X_69 = SYMMEDIAN POINT OF THE ANTICOMPLEMENTARY TRIANGLE (0.4122, 0.0654) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_298 = ISOTOMIC CONJUGATE OF 1st ISOGONIC CENTER (0.4724, 0.1301) X_5 = NINE-POINT CENTER (0.5561, 0.2489) X_302 = ISOTOMIC CONJUGATE OF 1st NAPOLEON POINT (0.5043, 0.1643) X_627 = ANTICOMPLEMENT OF X(17) (0.4791, 0.1233) A B C X17 X629 X2 X54 X69 X3 X298 X5 X302 X627 (a, b, c) = (5, 6, 7) | AB = 1

X627 (ANTICOMPLEMENT OF X17) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(f(a,b,c) : f(b,c,a) : f(c,a,b)\), where \(f(a,b,c) = [S_{B}S_{C} + 2S_{A}(a^{2} + \sqrt{3} \operatorname{area})]/a\)
Barycentrics: \(g(a,b,c) : g(b,c,a) : g(c,a,b)\), where \(g(a,b,c) = af(a,b,c)\)
Search Value (6, 9, 13): \(5.114797277327\)
▸ Alternate Coordinates1 form
  • Trilinears: \(F(17)/a - 2 \sec(A - \pi /3) : F(17)/b - 2 \sec(B - \pi /3) : F(17)/c - 2 \sec(C - \pi /3)\)

X627 lies on the Napoleon cubic.

▸ Incident Central Lines9 lines

{2, 17}, {3, 298}, {4, 616}, {5, 302}, {16, 635}, {20, 621}, {54, 69}, {61, 618}, {140, 299}

▸ Functional Relations7 relations

Notes

Erect equilateral triangles outwards on the sides of triangle ABC; the circumcenter of the apices is X627. (Peter Moses, 7/16,2003)

Let A' be the isogonal conjugate of the A-vertex of the inner Napoleon triangle, and define B' and C' cyclically. Triangle A'B'C' is perspective to the inner Napoleon triangle at X5, and to the outer Napoleon triangle at X627. (Randy Hutson, June 7, 2019)

Let OA be the circle centered at the A-vertex of the outer Fermat triangle and passing through A; define OB and OC cyclically. X627 is the radical center of OA, OB, OC. (Randy Hutson, August 30, 2020)