X547

MIDPOINT OF X2 AND X5

X547 is the midpoint of X2 and X5.
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 2, 5 }: Euler Line { 551, 952 }: Central Line L(551, 952) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_2 = CENTROID (0.5374, 0.2000) X_5 = NINE-POINT CENTER (0.5561, 0.2489) X_551 = MIDPOINT OF X(1) AND X(2) (0.5544, 0.2166) X_952 = INTERSECTION OF X(1)X(5) AND X(3)X(8) (0.1267, 0.6191) X_547 = MIDPOINT OF X(2) AND X(5) (0.5468, 0.2244) A B C X2 X5 X551 X952 X547 (a, b, c) = (5, 6, 7) | AB = 1

X547 (MIDPOINT OF X2 AND X5) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(5 \cos(B - C) + 2 \cos A : :\)
Search Value (6, 9, 13): \(1.591120267062\)
▸ Alternate Coordinates1 form
  • Trilinears: \(7 \cos A + 10 \cos B \cos C : 7 \cos B + 10 \cos C \cos A : 7 \cos C + 10 \cos A \cos B\)

▸ Linear Combinations1 combination

X547 lies on the Euler line. (Antreas Hatzipolakis, 1/20/00, Hyacinthos #201)

▸ Incident Central Lines2 lines

{2, 3}, {551, 952}

▸ Functional Relations8 relations

Notes

As a point on the Euler line, X547 has Shinagawa coefficients \((7,3)\).