X442

COMPLEMENT OF SCHIFFLER POINT

X442 is the complement of Schiffler point.
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 79, 191 }: Central Line L(79, 191) { 2, 3 }: Euler Line { 10, 12 }: Central Line L(10, 12) { 9, 46 }: Central Line L(9, 46) { 11, 214 }: Central Line L(11, 214) { 115, 120 }: Central Line L(115, 120) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_79 = ISOGONAL CONJUGATE OF X(35) (0.5976, 0.3019) X_191 = -CEVA CONJUGATE OF X(1) (0.4859, 0.1209) X_2 = CENTROID (0.5374, 0.2000) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_10 = SPIEKER CENTER (0.5204, 0.1833) X_12 = {X(1),X(5)}-HARMONIC CONJUGATE OF X(11) (0.5641, 0.2407) X_9 = MITTENPUNKT (0.5110, 0.1615) X_46 = -CEVA CONJUGATE OF X(1) (0.6917, 0.4543) X_11 = FEUERBACH POINT (0.7347, 0.0667) X_214 = -CEVA CONJUGATE OF X(44) (0.3571, 0.3499) X_115 = CENTER OF KIEPERT HYPERBOLA (0.7507, 0.0838) X_120 = -OF-MEDIAL-TRIANGLE (0.3204, 0.3466) X_442 = COMPLEMENT OF SCHIFFLER POINT (0.5418, 0.2114) A B C X79 X191 X2 X3 X10 X12 X9 X46 X11 X214 X115 X120 X442 (a, b, c) = (5, 6, 7) | AB = 1

X442 (COMPLEMENT OF SCHIFFLER POINT) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(bc(v + w) : ca(w + u) : ab(u + v)\), where \(u : v : w\) = X284; e.g., \(u(A,B,C) = (\sin A)/(\cos B + \cos C)\)
Barycentrics: \(v + w : w + u : u + v\)
Search Value (6, 9, 13): \(2.355469758576\)
▸ Incident Central Lines11 lines

{2, 3}, {8, 495}, {9, 46}, {10, 12}, {11, 214}, {100, 943}, {115, 120}, {119, 125}, {274, 325}, {388, 956}, {392, 946}

▸ Functional Relations12 relations

Notes

As a point on the Euler line, X442 has Shinagawa coefficients \((\$aS_{A}\$ + abc,\$aS_{A}\$ - abc)\)

Let IA, IB, IC be the excenters, let AB, AC be the projections of A onto IAIB and IAIC, respectively, and define BC, BA and CA, CB cyclically. The Euler lines of the four triangles ABC, AABAC, BBCBA, CCACB concur in X442. (Jean-Pierre Ehrmann, 11/24/01)

In the plane of triangle ABC, let DEF denote the intouch triangle of ABC, and let

  • HA = orthocenter of IBC

  • MA = midpoint of segment BC

  • NA = midpoint of the arc BC which does not include A

  • \(S_{A}\) = reflection of I in line DE,

  • and define cyclically the points HB, HC, MB, MC, NB, NC, and \(S_{B}\), \(S_{C}\). The lines \(S_{A}\)MA, \(S_{B}\)MB, \(S_{CA}\)MC concur in X442, and X442 is the pole, with respect to the incircle, of the perspectrix of the triangles HAHBHC and NANBNC. (Dominik Burek, January 18 2012)

Let JaJbJc be the excentral triangle. X442 is the radical center of the nine-point circles of JaBC, JbCA, JcAB. (Randy Hutson, September 14, 2016)

Let (Ja) be the A-excircle of the A-altimedial triangle, and define (Jb) and (Jc) cyclically. X442 is the radical center of (Ja), (Jb), (Jc). (Randy Hutson, November 2, 2017)