X415¶
X4-HIRST INVERSE OF X29
X415 (X4-HIRST INVERSE OF X29) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).¶
Constructed Elements
Central Lines: {2, 3} (Euler line), {162, 238}
Related Centers: X2 (CENTROID), X3 (CIRCUMCENTER), X4 (ORTHOCENTER), X162 (CEVAPOINT OF X108 AND X109), X238 (-LINE CONJUGATE OF X37)
Alternate Coordinates1 form
Barycentrics: \((a + b) \cdot (a + c) \cdot (a^{2} + b^{2} - c^{2}) \cdot (a^{2} - b^{2} + c^{2}) \cdot (a^{3} - 2 a^{2} b + b^{3} - 2 a^{2} c + a b c + c^{3}) : :\)
Incident Central Lines16 lines
Functional Relations12 relations
X415 = polar conjugate of X11608
X415 = polar conjugate of the isotomic conjugate of X40882
X415 = polar conjugate of the isogonal conjugate of X5060
X415 = X243-Ceva conjugate of X2659
X415 = Xi-cross conjugate of Xj for these (i,j): {1758, 2651}, {5060, 40882}
X415 = Xi-isoconjugate of Xj for these (i,j): {3, 2652}, {48, 11608}, {65, 17973}, {73, 2648}, {656, 2701}, {810, 35154}, {1214, 17963}, {1409, 17947}, {6516, 18000}, {18013, 36059}
X415 = Xi-Dao conjugate of Xj for these (i,j): {525, 35086}, {1214, 39055}, {1249, 11608}, {2652, 36103}, {2701, 40596}, {17973, 40602}, {18013, 20620}, {35154, 39062}
X415 = trilinear pole of line {2785, 41499}
X415 = barycentric product Xi*Xj for these {i,j}: {4, 40882}, {29, 17950}, {92, 2651}, {264, 5060}, {333, 17985}, {648, 2785}, {1758, 31623}, {3064, 17933}, {5075, 6331}, {17942, 46110}, {17966, 44130}, {35145, 41499}
X415 = barycentric quotient Xi/Xj for these {i,j}: {4, 11608}, {19, 2652}, {29, 17947}, {112, 2701}, {284, 17973}, {648, 35154}, {1172, 2648}, {1758, 1214}, {2299, 17963}, {2651, 63}, {2785, 525}, {3064, 18013}, {5060, 3}, {5075, 647}, {17942, 1813}, {17950, 307}, {17966, 73}, {17975, 40152}, {17985, 226}, {40882, 69}, {41499, 8680}, {51643, 51640}
X415 = {Xi,Xj}-harmonic conjugate of Xk for these (i,j,k): {4, 1982, 29}, {422, 468, 423}, {851, 52240, 416}, {860, 2074, 447}, {11110, 37383, 29}, {13739, 17555, 29}
Notes¶
As a point on the Euler line, X415 has Shinagawa coefficients 3\(\$bcS_{B}S_{C}\$\)F + (E - 2F)\(FS^{2}\), -(E + F)*\(\$bcS_{B}S_{C}\$\) + (E + F)\(FS^{2}\) - \(S^{4})\).