X3943

X44com[INVERSE(n(INCENTRAL TRIANGLE))]

X3943 = complement of X17160
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 10, 37 }: Central Line L(10, 37) { 8, 45 }: Central Line L(8, 45) { 6, 145 }: Central Line L(6, 145) { 141, 192 }: Central Line L(141, 192) { 44, 519 }: Central Line L(44, 519) { 190, 524 }: Central Line L(190, 524) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_10 = SPIEKER CENTER (0.5204, 0.1833) X_37 = CROSSPOINT OF INCENTER AND CENTROID (0.5567, 0.2158) X_8 = NAGEL POINT (0.4694, 0.1333) X_45 = -BETH CONJUGATE OF X(1) (0.5418, 0.1981) X_6 = SYMMEDIAN POINT (LEMOINE POINT, GREBE POINT) (0.6000, 0.2672) X_145 = ANTICOMPLEMENT OF NAGEL POINT (0.6735, 0.3333) X_141 = COMPLEMENT OF SYMMEDIAN POINT (0.5061, 0.1663) X_192 = -CEVA CONJUGATE OF X(2) (CONGRUENT PARALLELIANS POINT) (0.6147, 0.2635) X_44 = -LINE CONJUGATE OF X(1) (2.1429, 2.0996) X_519 = ISOGONAL CONJUGATE OF X(106) (0.9566, 0.6107) X_190 = YFF PARABOLIC POINT (0.0748, 0.3999) X_524 = ISOGONAL CONJUGATE OF X(111) (0.1376, -0.2297) X_3943 = com[INVERSE(n(INCENTRAL TRIANGLE))] (-3.3673, -3.2993) A B C X10 X37 X8 X45 X6 X145 X141 X192 X44 X519 X190 X524 X3943 (a, b, c) = (5, 6, 7) | AB = 1

X3943 (X44com[INVERSE(n(INCENTRAL TRIANGLE))]) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Barycentrics: \(f(a,b,c) : f(b,c,a) : f(c,a,b)\), where \(f(a,b,c) = (b + c)(b + c - 2a)\)
Search Value (6, 9, 13): \(23.451127068143\)
▸ Incident Central Lines23 lines

{6, 145}, {8, 45}, {9, 3632}, {10, 37}, {44, 519}, {101, 2758}, {141, 192}, {190, 524}, {306, 3175}, {320, 545}, {523, 661}, {536, 1086}, {1018, 2245}, {1100, 3635}, {1317, 1404}, {1897, 1990}, {2171, 3649}, {2345, 3616}, {3247, 3624}, {3625, 3707}, {3636, 3723}, {3644, 3662}, {3672, 3763}

▸ Functional Relations1 relation

  • X3943 = complement of X17160