X3543

EULER LINE INTERCEPT OF LINE X146X_148

X3543 = midpoint of X2 and X3146
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 2, 3146 }: Euler Line { 2, 3 }: Euler Line { 146, 148 }: Central Line L(146, 148) { 253, 317 }: Central Line L(253, 317) { 153, 528 }: Central Line L(153, 528) { 147, 543 }: Central Line L(147, 543) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_2 = CENTROID (0.5374, 0.2000) X_3146 = -CEVA CONJUGATE OF X(2) (0.8367, 0.9831) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_146 = REFLECTION OF X(20) IN X(110) (0.1155, 1.2873) X_148 = STEINER POINT OF ANTICOMPLEMENTARY TRIANGLE (1.3904, -0.2646) X_253 = -CROSS CONJUGATE OF X(2) (3.5087, 32.5688) X_317 = ISOTOMIC CONJUGATE OF X(68) (0.6796, 0.5070) X_153 = REFLECTION OF X(20) IN X(100) (-0.1020, 1.1248) X_528 = DIRECTION OF VECTOR AX + BX + CX, where X = X(11) (1.0237, -0.1286) X_147 = TARRY POINT OF ANTICOMPLEMENTARY TRIANGLE (-0.1660, 1.0561) X_543 = DIRECTION OF VECTOR AX + BX + CX, where X = X(99) (0.0220, 0.4806) X_3543 = EULER LINE INTERCEPT OF LINE X(146)X(148) (0.6871, 0.5915) A B C X2 X3146 X3 X146 X148 X253 X317 X153 X528 X147 X543 X3543 (a, b, c) = (5, 6, 7) | AB = 1

X3543 (EULER LINE INTERCEPT OF LINE X146X_148) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(6 \cos B \cos C - \sin B \sin C : :\)
Search Value (6, 9, 13): \(-13.982607614342\)
▸ Linear Combinations1 combination
▸ Incident Central Lines19 lines

{2, 3}, {144, 3419}, {146, 148}, {147, 543}, {152, 544}, {153, 528}, {253, 317}, {371, 1131}, {372, 1132}, {388, 3058}, {390, 1478}, {393, 3163}, {515, 3241}, {519, 962}, {541, 3448}, {551, 1699}, {553, 938}, {671, 2794}, {1503, 1992}

▸ Functional Relations10 relations

Notes

As a point on the Euler line, X3543 has Shinagawa coefficients \((1, -6)\).

Let Pa be the parabola with focus A and directrix BC. Let La be the polar of X3 wrt Pa. Define Lb and Lc cyclically. Let A' = Lb∩Lc, B' = Lc∩La, C' = La∩Lb. Then X3543 = X193-of-A'B'C'. (Randy Hutson, September 5, 2015)