X3060

INTERSECTION OF LINES X2X_51 AND X4X_52

X3060 = reflection of X2 in X51
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 2, 51 }: Central Line L(2, 51) { 6, 22 }: Central Line L(6, 22) { 4, 52 }: Central Line L(4, 52) { 26, 54 }: Central Line L(26, 54) { 25, 110 }: Central Line L(25, 110) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_2 = CENTROID (0.5374, 0.2000) X_51 = CENTROID OF ORTHIC TRIANGLE (0.6093, 0.3186) X_6 = SYMMEDIAN POINT (LEMOINE POINT, GREBE POINT) (0.6000, 0.2672) X_22 = EXETER POINT (0.4143, -0.1221) X_4 = ORTHOCENTER (0.6122, 0.3958) X_52 = ORTHOCENTER OF ORTHIC TRIANGLE (0.7155, 0.4580) X_26 = CIRCUMCENTER OF THE TANGENTIAL TRIANGLE (0.1382, -0.8447) X_54 = KOSNITA POINT (0.5880, 0.2176) X_25 = HOMOTHETIC CENTER OF ORTHIC AND TANGENTIAL TRIANGLES (0.6329, 0.4497) X_110 = FOCUS OF KIEPERT PARABOLA (0.2516, 0.5478) X_3060 = INTERSECTION OF LINES X(2)X(51) AND X(4)X(52) (0.6811, 0.4372) A B C X2 X51 X6 X22 X4 X52 X26 X54 X25 X110 X3060 (a, b, c) = (5, 6, 7) | AB = 1

X3060 (INTERSECTION OF LINES X2X_51 AND X4X_52) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(a(b^{2}c^{2} + c^{2}a^{2} + a^{2}b^{2} - b^{4} - c^{4}) : :\)
Search Value (6, 9, 13): \(-2.388117627074\)
▸ Alternate Coordinates1 form
  • Trilinears: \(\sin A (\sin 2B + \sin 2C) - \sin B \sin C : :\)

▸ Incident Central Lines16 lines

{2, 51}, {3, 143}, {4, 52}, {6, 22}, {20, 389}, {23, 184}, {25, 110}, {26, 54}, {143, 1173}, {156, 195}, {371, 588}, {372, 589}, {394, 1995}, {648, 1629}, {1853, 2781}, {1992, 2393}

▸ Functional Relations10 relations

Notes

X3060 is the second of three Spanish Points developed by Antreas P. Hatzipolakis and Javier Garcia Capitan in 2009; see X3567.

Let A' be the trilinear pole of the perpendicular bisector of BC, and define B' and C' cyclically. A'B'C' is also the anticomplement of the anticomplement of the midheight triangle. X3060 = X2-of-A'B'C'. (Randy Hutson, January 29, 2018)