X2185

X2-ISOCONJUGATE OF X181

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 21, 60 }: Central Line L(21, 60) { 27, 86 }: Central Line L(27, 86) { 261, 284 }: Central Line L(261, 284) { 2, 662 }: Central Line L(2, 662) { 81, 593 }: Central Line L(81, 593) { 55, 643 }: Central Line L(55, 643) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_2171 = -ISOCONJUGATE OF X(60) (0.5931, 0.2753) X_21 = SCHIFFLER POINT (0.5287, 0.1771) X_60 = ISOGONAL CONJUGATE OF X(12) (0.5790, 0.2258) X_27 = CEVAPOINT OF ORTHOCENTER AND CLAWSON CENTER (0.6182, 0.4112) X_86 = CEVAPOINT OF INCENTER AND CENTROID (0.5534, 0.2171) X_261 = ISOTOMIC CONJUGATE OF X(12) (0.5072, 0.1625) X_284 = -CROSS CONJUGATE OF X(21) (0.5646, 0.2088) X_2 = CENTROID (0.5374, 0.2000) X_662 = TRILINEAR POLE OF LINE X(1)X(21) (0.1811, 0.4951) X_81 = CEVAPOINT OF INCENTER AND SYMMEDIAN POINT (0.5849, 0.2510) X_593 = 1st HATZIPOLAKIS-YIU POINT (0.6202, 0.3026) X_55 = INSIMILICENTER(CIRCUMCIRCLE, INCIRCLE) (0.5490, 0.1921) X_643 = TRILINEAR MULTIPLIER FOR KIEPERT PARABOLA (0.0142, 0.3704) X_2185 = -ISOCONJUGATE OF X(181) (0.5454, 0.1933) A B C X2171 X21 X60 X27 X86 X261 X284 X2 X662 X81 X593 X55 X643 X2185 (a, b, c) = (5, 6, 7) | AB = 1

X2185 (X2-ISOCONJUGATE OF X181) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \((a - b - c)/(b + c)^{2} : :\)
Barycentrics: \(a^{2}/f(a,b,c) : b^{2}/f(b,c,a) : c^{2}/f(c,a,b)\)
Search Value (6, 9, 13): \(2.777973913915\)
▸ Incident Central Lines13 lines

{1, 849}, {2, 662}, {21, 60}, {27, 86}, {55, 643}, {81, 593}, {110, 1621}, {171, 1326}, {222, 1414}, {261, 284}, {312, 2268}, {501, 1125}, {552, 553}

▸ Functional Relations10 relations

Notes

Let DEF be the cevian triangle of the incenter. Let OA be the circumcircle of AEF. Let T1 be the line tangent to OA at E, and let T2 be the line tangent to OA at F. Let AB = T1∩BC and AC = T2∩BC, and let A' be the radical center of the circumcircles of AEF, BFAB, CAAC.. Define B' and C' cyclically. The lines AA', BB', CC' concur in X2185. (Angel Montesdeoca, January 4, 2021)