X942

INCIRCLE-INVERSE OF X36

X942 is the incircle-inverse of X36.
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 1, 65 }: OI Line (Incenter–Circumcenter Line) { 1, 3 }: OI Line (Incenter–Circumcenter Line) { 4, 7 }: Central Line L(4, 7) { 2, 72 }: Central Line L(2, 72) { 28, 60 }: Central Line L(28, 60) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_1 = INCENTER (0.5714, 0.2333) X_65 = ORTHOCENTER OF THE INTOUCH TRIANGLE (0.6041, 0.2933) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_4 = ORTHOCENTER (0.6122, 0.3958) X_7 = GERGONNE POINT (0.5903, 0.2769) X_2 = CENTROID (0.5374, 0.2000) X_72 = ISOGONAL CONJUGATE OF X(28) (0.4367, 0.0733) X_28 = CEVAPOINT OF X(19) AND X(25) (0.6285, 0.4382) X_60 = ISOGONAL CONJUGATE OF X(12) (0.5790, 0.2258) X_942 = INCIRCLE-INVERSE OF X(36) (0.5878, 0.2633) A B C X1 X65 X3 X4 X7 X2 X72 X28 X60 X942 (a, b, c) = (5, 6, 7) | AB = 1

X942 (INCIRCLE-INVERSE OF X36) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(2abc + (b + c)(a - b + c)(a + b -c) : :\)
Barycentrics: \(g(a,b,c) : g(b,c,a) : g(c,a,b)\), where \(g(a,b,c) = af(a,b,c)\)
Search Value (6, 9, 13): \(1.110017411481\)
▸ Alternate Coordinates1 form
  • Trilinears: \(1 + \cos B + \cos C : :\)

▸ Incident Central Lines27 lines

{1, 3}, {2, 72}, {4, 7}, {5, 226}, {6, 169}, {8, 443}, {10, 141}, {11, 113}, {28, 60}, {30, 553}, {34, 222}, {37, 579}, {42, 1066}, {58, 1104}, {63, 405}, {78, 474}, {212, 582}, {238, 1046}, {277, 1002}, {279, 955}, {284, 501}, {355, 388}, {496, 946}, {750, 976}, {758, 960}, {962, 1058}, {1042, 1064}

▸ Functional Relations21 relations

Notes

Let IaIbIc be the incentral triangle of triangle ABC. Let LA be the line of reflection of line BC in line IbIc, and define LB and LC cyclically. Let A″ = LB∩LC, and define B″ and C″ cyclically. The lines AA″, BB″, CC″ concur in X942. (Randy Hutson, 9/23/2011)

Let I be the incenter of ABC. Let NA be the nine-point center of the triangle IBC, and define NB and NC cyclically. Let AA be the reflection of NA in the line AI, Let AB be the reflection of NA in the line BI, let Let AC be the reflection of NA in the line CI, and define BA, BB, and BC cyclically, and define CA, CB, and CC cyclically. Let OA be the nine-point center of the triangle AAABAC, let OB be the nine-point center of the triangle BABBBC, and let OC be the nine-point center of the triangle CACBCC. The circles OA, OB, OC concur in X942. (Antreas Hatzipolakis and César Lozada, January 28, 2015, Hyacinthos 23074)

X942 is the center of the conic which is the locus of poles, wrt the incircle, of tangents to the circumcircle. This conic has foci at X1 and X65. (Randy Hutson, July 20, 2016)

Let TaTbTc be the intouch triangle. Let A″ be the orthocenter of ATbTc, and define B″ and C″ cyclically. The triangle A″B″C″ is homothetic to TaTbTc, and the center of homothety is X942. (Randy Hutson, July 20, 2016)

Let HaHbHc be the orthic triangle. Let A″ be the incenter of AHbHc, and define B″ and C″ cyclically. The triangle A″B″C″ is homothetic to the intouch triangle, and the center of homothety is X942. (Randy Hutson, July 20, 2016)

Let A' be the homothetic center of the orthic triangles of the intouch and A-extouch triangles, and define B' and C' cyclically. The triangle A'B'C' is perspective to the half-altitude triangle at X942. In fact, A'B'C' is the cevian triangle of X942, wrt the half-altitude triangle. (Randy Hutson, July 20, 2016)

A construction of X942 is given at 24080. (Antreas Hatzipolakis, August 29, 2016)