X562

TRILINEAR QUOTIENT X2*X50/X49

X562 = polar conjugate of X30529
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 4, 93 }: Central Line L(4, 93) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_4 = ORTHOCENTER (0.6122, 0.3958) X_93 = ISOGONAL CONJUGATE OF X(49) (0.5299, 0.2878) X_562 = TRILINEAR QUOTIENT X(2)*X(50)/X(49) (3.1429, 3.7154) A B C X4 X93 X562 (a, b, c) = (5, 6, 7) | AB = 1

X562 (TRILINEAR QUOTIENT X2*X50/X49) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(\csc A \tan 3A : \csc B \tan 3B : \csc C \tan 3C\)
Barycentrics: \(\tan 3A : \tan 3B : \tan 3C\)
Search Value (6, 9, 13): \(50.090809847426\)
▸ Linear Combinations1 combination
  • = \((3S^{2} - S^{2}_{A})(3S^{2} - S^{2}_{B})(3S^{2} - S^{2}_{C})\) X3 - \(16S_{A}\)\(S_{B}\)\(S_{C}(5S_{A}S_{B}S_{C} + 3S^{2}S_{\omega }S)\) X3519 (Peter Moses, January 29, 2015)

▸ Incident Central Lines2 lines

{4, 93}, {252, 6143}

▸ Functional Relations1 relation
  • X562 = polar conjugate of X30529

Notes

Clark Kimberling and Cyril Parry, “Products, Square Roots, and Layers in Triangle Geometry,” Mathematics and Informatics Quarterly 10 (2000) 9-22; on page 21, section 8.