X550

MIDPOINT OF X3 AND X20

X550 is the midpoint of X3 and X20.
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 3, 20 }: Euler Line { 15, 397 }: Central Line L(15, 397) { 16, 398 }: Central Line L(16, 398) { 165, 355 }: Central Line L(165, 355) { 35, 495 }: Central Line L(35, 495) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_3 = CIRCUMCENTER (0.5000, 0.1021) X_20 = DE LONGCHAMPS POINT (0.3878, -0.1916) X_15 = 1st ISODYNAMIC POINT (0.5519, 0.1878) X_397 = CROSSPOINT OF X(4) AND X(17) (0.6029, 0.2975) X_16 = 2nd ISODYNAMIC POINT (1.8453, 2.3239) X_398 = CROSSPOINT OF X(4) AND X(18) (0.5945, 0.2099) X_165 = CENTROID OF THE EXCENTRAL TRIANGLE (0.4762, 0.0583) X_355 = FUHRMANN CENTER (0.5408, 0.2645) X_35 = {X(1),X(3)}-HARMONIC CONJUGATE OF X(36) (0.5373, 0.1706) X_495 = JOHNSON MIDPOINT (0.5666, 0.2382) X_550 = MIDPOINT OF X(3) AND X(20) (0.4439, -0.0448) A B C X3 X20 X15 X397 X16 X398 X165 X355 X35 X495 X550 (a, b, c) = (5, 6, 7) | AB = 1

X550 (MIDPOINT OF X3 AND X20) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(- \cos(B - C) + 4 \cos A : :\)
Barycentrics: \(4 a^{4} - 3 a^{2} (b^{2} + c^{2}) - (b^{2} - c^{2})^{2} : :\)
Search Value (6, 9, 13): \(13.011854046758\)
▸ Alternate Coordinates5 forms
  • Trilinears: \(2 \sec A - 3 \sec B \sec C : 2 \sec B - 3 \sec C \sec A : 2 \sec C - 3 \sec A \sec B\)

  • Trilinears: \(6 \cos A + \cos B \cos C - 3 \sin B \sin C : :\)

  • Trilinears: \(\cos A - 4 \cos B \cos C + 2 \sin B \sin C : :\)

  • Trilinears: \(6 \cos B \cos C - 2 \sin B \sin C - \cos(B - C) : :\)

  • Trilinears: \(5 \cos A + \cos(B - C) - \cos B \cos C - 3 \sin B \sin C : :\)

▸ Linear Combinations1 combination
▸ Incident Central Lines9 lines

{2, 3}, {15, 397}, {16, 398}, {35, 495}, {36, 496}, {40, 952}, {74, 930}, {156, 1092}, {165, 355}

▸ Functional Relations17 relations

Notes

As a point on the Euler line, X550 has Shinagawa coefficients \((3,-5)\).

Let OA be the circle centered at the A-vertex of the anticomplementary triangle and passing through A; define OB and OC cyclically. X550 is the radical center of OA, OB, OC. (Randy Hutson, August 30, 2020)

Let OA be the circle centered at the A-vertex of the anti-Euler triangle and passing through A; define OB and OC cyclically. X550 is the radical center of OA, OB, OC. (Randy Hutson, August 30, 2020)