X493

1st VAN LAMOEN HOMOTHETIC CENTER

X493 is a homothetic center of triangles associated with squares that circumscribe ABC. For details, see Vierkanten in een driehoek: 4. Ingeschreven vierkanten (Floor van Lamoen, 4/27/98)
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 25, 371 }: Central Line L(25, 371) { 39, 494 }: Central Line L(39, 494) { 394, 1504 }: Central Line L(394, 1504) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_394 = -CEVA CONJUGATE OF X(3) (0.3778, 0.0284) X_494 = 2nd VAN LAMOEN HOMOTHETIC CENTER (0.8529, 0.5391) X_25 = HOMOTHETIC CENTER OF ORTHIC AND TANGENTIAL TRIANGLES (0.6329, 0.4497) X_371 = KENMOTU POINT (CONGRUENT SQUARES POINT) (0.5652, 0.2097) X_39 = BROCARD MIDPOINT (0.5778, 0.2305) X_1504 = INSIMILICENTER OF MOSES AND 2nd LEMOINE CIRCLES (0.5879, 0.2472) X_493 = 1st VAN LAMOEN HOMOTHETIC CENTER (0.5707, 0.2293) A B C X394 X494 X25 X371 X39 X1504 X493 (a, b, c) = (5, 6, 7) | AB = 1

X493 (1st VAN LAMOEN HOMOTHETIC CENTER) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(1/(\sin A + \sin B \sin C) : :\)
Barycentrics: \((\sin A)/(\sin A + \sin B \sin C) : :\)
Search Value (6, 9, 13): \(1.847641056142\)
▸ Alternate Coordinates1 form
  • Barycentrics: \(a^{2}/(a^{2} + S) : :\)

▸ Incident Central Lines3 lines

{25, 371}, {39, 494}, {394, 1504}

▸ Functional Relations4 relations

Notes

X493 is the homothetic center of triangle ABC and the Lucas homothetic triangle; see X371. Writing t for the ratio L:W at X371, let LA be the line through the intersections, other than A, of the A-Lucas(t) circle and sides CA and AB. Define LB and LC cyclically. Let A' = LB∩LC, and define B' and C' cyclically. Then the triangle A'B'C', here introduced as the Lucas(t) homothetic triangle, is homothetic to triangle ABC. If t = 1, the center of homothety is X493; for t = -1, it is X494; for t = 2, it is X588; and for t = -2, it is X589. (Randy Hutson, February 9, 2013)

Let A″ be the intersection of line BC and the common tangent to the B- and C-Lucas circles (at their touchpoint). Define B″ and C″ cyclically. Then A″B″C″ is the cevian triangle of X493. Also, X493 is the point of intersection of the tangents at X371 and X485 to the orthocubic K006. (Randy Hutson, July 23, 2015)