X369

1st TRISECTED PERIMETER POINT

There exist points A', B', C' on segments BC, CA, AB, respectively, such that AB' + AC' = BC' + BA' = CA' + CB' = (a + b + c)/3, and the lines AA', BB', CC' concur in X369. Near the end of the 20th century, Yff found trilinears for X369 in terms of the unique real root, r, of the cubic polynomial
< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_369 = 1st TRISECTED PERIMETER POINT (0.6760, -0.0539) A B C X369 (a, b, c) = (5, 6, 7) | AB = 1

X369 (1st TRISECTED PERIMETER POINT) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Trilinears: \(x : y : z (see below)\)
Barycentrics: \(ax : by : cz\)
Search Value (6, 9, 13): \(2.053651811125\)

Notes

\(2t^{3}\) - 3(a + b + c)\(t^{2}\) + (\(a^{2}\) + \(b^{2}\) + \(c^{2}\) + 8bc + 8ca + 8ab)t - (\(cb^{2}\) + \(ac^{2}\) + \(ba^{2}\) + \(5bc^{2}\) + \(5ca^{2}\) + \(5ab^{2}\) + 9abc),

as follows: x = bc(r - c + a)(r - a + b). Here x(a,c,b) ≠ x(a,b,c), so that y and z are not obtained from x by cyclically permutating a,b,c. At the geometry conference held at Miami University of Ohio, October 2, 2004, Yff, proved that X369 is also given by \(x_{1} : y_{1} : z_{1}\) where \(y_{1}\) : \(z_{1}\) are given by cyclic permutations of a,b,c, in \(x_{1}\), where

\(x_{1}\) = bc[\(r^{2}\) - (2c + a)r + (- \(a^{2}\) + \(b^{2}\) + \(2c^{2}\) + 2bc + 3ca + 2ab].

His presentation included a proof that there is only one point for which AB' + AC' = BC' + BA' = CA' + CB' .