X281¶
X37-CROSS CONJUGATE OF X9
X281 (X37-CROSS CONJUGATE OF X9) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).¶
Constructed Elements
Central Lines: {4, 9}, {8, 29}
Related Centers: X37 (CROSSPOINT OF INCENTER AND CENTROID), X9 (MITTENPUNKT), X4 (ORTHOCENTER), X8 (NAGEL POINT), X29 (CEVAPOINT OF INCENTER AND ORTHOCENTER)
Alternate Coordinates5 forms
Trilinears: \(\csc A + 2 \csc 2A : \csc B + 2 \csc 2B : \csc C + 2 \csc 2C\)
Trilinears: \((1 + \sec A)/a : (1 + \sec B)/b : (1 + \sec C)/c\)
Trilinears: \((b + c - a) \sec A : :\)
Barycentrics: \(1 + \sec A : 1 + \sec B : 1 + \sec C\)
Barycentrics: \((b + c - a)/(b^{2} + c^{2} - a^{2}) : :\)
Incident Central Lines23 lines
Functional Relations14 relations
X281 = isotomic conjugate of X348
X281 = complement of X347
X281 = Xi-Ceva conjugate of Xj for these (i,j): (29, 33), (92, 4)
X281 = Xi-cross conjugate of Xj for these (i,j): (33, 4), (37, 9), (55, 8)
X281 = crosspoint of Xi and Xj for these (i,j): (2, 280), (92, 318)
X281 = crosssum of Xi and Xj for these (i,j): (6, 221), (48, 603), (73, 1409), (652, 1364)
X281 = pole, wrt polar circle, of Gergonne line
X281 = X48-isoconjugate (polar conjugate) of X7
X281 = crossdifference of every pair of points on line X1459X1946
X281 = trilinear pole of line X3064X3700 (the polar of X7 wrt polar circle)
X281 = perspector of Gemini triangle 37 and cross-triangle of ABC and Gemini triangle 37
X281 = trilinear pole of line X3064X3700 (the perspectrix of ABC and Gemini triangle 38)
Notes¶
X281: Let TaTbTc be the intouch triangle. Let A″ be the pole, wrt the polar circle, of line TbTc, and define B″, C″ cyclically. The lines AA″, BB″, CC″ concur in X281. (Randy Hutson, September 14, 2016)
Let A'B'C' be the 3rd extouch triangle. Let A″ be the pole, wrt the polar circle, of line B'C', and define B″, C″ cyclically. The triangle A'B'C' is homothetic to ABC at X281. (Randy Hutson, September 14, 2016)
Let A'B'C' be the 4th extouch triangle. Let A″ be the pole, wrt the polar circle, of line B'C', and define B″, C″ cyclically. The lines AA″, BB″, CC″ concur in X281. (Randy Hutson, September 14, 2016)
Let A'B'C' be the 5th extouch triangle. Let A″ be the pole, wrt the polar circle, of line B'C', and define B″ and C″ cyclically. The lines AA″, BB″, CC″ concur in X281. (Randy Hutson, September 14, 2016)
Let Ea be the ellipse passing through A, and with foci at B and C (the A-Soddy ellipse). Let La be the polar of X3 with respect to Ea. Define Lb and Lc cyclically. Let A' = Lb∩Lc, B' = Lc∩La, C' = La∩Lb. Triangle A'B'C' is homothetic to ABC, and the center of homothety is X281. (Randy Hutson, September 14, 2016)