X281

X37-CROSS CONJUGATE OF X9

< A B C >: Reference Triangle △ABC [ A B ]: Sideline AB (Base c = 1) [ B C ]: Sideline BC (Side a) [ C A ]: Sideline CA (Side b) { 4, 9 }: Orthocenter–Spieker Line { 8, 29 }: Central Line L(8, 29) { 2, 92 }: Central Line L(2, 92) { 45, 53 }: Central Line L(45, 53) { 37, 158 }: Central Line L(37, 158) { 33, 200 }: Central Line L(33, 200) A = Vertex A (0.0000, 0.0000) B = Vertex B (1.0000, 0.0000) C = Vertex C (0.6122, 0.5999) X_37 = CROSSPOINT OF INCENTER AND CENTROID (0.5567, 0.2158) X_9 = MITTENPUNKT (0.5110, 0.1615) X_4 = ORTHOCENTER (0.6122, 0.3958) X_8 = NAGEL POINT (0.4694, 0.1333) X_29 = CEVAPOINT OF INCENTER AND ORTHOCENTER (0.5903, 0.3384) X_2 = CENTROID (0.5374, 0.2000) X_92 = CEVAPOINT OF INCENTER AND CLAWSON POINT (0.5949, 0.3639) X_45 = -BETH CONJUGATE OF X(1) (0.5418, 0.1981) X_53 = SYMMEDIAN POINT OF ORTHIC TRIANGLE (0.6164, 0.4390) X_158 = -CROSS CONJUGATE OF X(92) (0.6215, 0.5117) X_33 = PERSPECTOR OF THE ORTHIC AND INTANGENTS TRIANGLES (0.6019, 0.3546) X_200 = -CEVA CONJUGATE OF X(9) (0.4392, 0.1037) X_281 = -CROSS CONJUGATE OF X(9) (0.5796, 0.3202) A B C X37 X9 X4 X8 X29 X2 X92 X45 X53 X158 X33 X200 X281 (a, b, c) = (5, 6, 7) | AB = 1

X281 (X37-CROSS CONJUGATE OF X9) constructed on acute reference triangle \((a, b, c) = (5, 6, 7)\) with unit baseline AB = \(1\).

Constructed Elements

Trilinears: \(\sec A \cot A/2 : \sec B \cot B/2 : \sec C \cot C/2\)
Barycentrics: \(\tan A \cot A/2 : \tan B \cot B/2 : \tan C \cot C/2\)
Search Value (6, 9, 13): \(5.042882205225\)
▸ Alternate Coordinates5 forms
  • Trilinears: \(\csc A + 2 \csc 2A : \csc B + 2 \csc 2B : \csc C + 2 \csc 2C\)

  • Trilinears: \((1 + \sec A)/a : (1 + \sec B)/b : (1 + \sec C)/c\)

  • Trilinears: \((b + c - a) \sec A : :\)

  • Barycentrics: \(1 + \sec A : 1 + \sec B : 1 + \sec C\)

  • Barycentrics: \((b + c - a)/(b^{2} + c^{2} - a^{2}) : :\)

▸ Incident Central Lines23 lines

{1, 282}, {2, 92}, {4, 9}, {6, 1146}, {7, 653}, {8, 29}, {28, 958}, {33, 200}, {37, 158}, {45, 53}, {48, 944}, {100, 1013}, {189, 222}, {196, 226}, {220, 594}, {240, 984}, {264, 344}, {268, 1012}, {318, 346}, {380, 950}, {451, 1068}, {515, 610}, {612, 1096}

▸ Functional Relations14 relations

Notes

X281: Let TaTbTc be the intouch triangle. Let A″ be the pole, wrt the polar circle, of line TbTc, and define B″, C″ cyclically. The lines AA″, BB″, CC″ concur in X281. (Randy Hutson, September 14, 2016)

Let A'B'C' be the 3rd extouch triangle. Let A″ be the pole, wrt the polar circle, of line B'C', and define B″, C″ cyclically. The triangle A'B'C' is homothetic to ABC at X281. (Randy Hutson, September 14, 2016)

Let A'B'C' be the 4th extouch triangle. Let A″ be the pole, wrt the polar circle, of line B'C', and define B″, C″ cyclically. The lines AA″, BB″, CC″ concur in X281. (Randy Hutson, September 14, 2016)

Let A'B'C' be the 5th extouch triangle. Let A″ be the pole, wrt the polar circle, of line B'C', and define B″ and C″ cyclically. The lines AA″, BB″, CC″ concur in X281. (Randy Hutson, September 14, 2016)

Let Ea be the ellipse passing through A, and with foci at B and C (the A-Soddy ellipse). Let La be the polar of X3 with respect to Ea. Define Lb and Lc cyclically. Let A' = Lb∩Lc, B' = Lc∩La, C' = La∩Lb. Triangle A'B'C' is homothetic to ABC, and the center of homothety is X281. (Randy Hutson, September 14, 2016)