GC-06.04 · Symbolic Model & Source¶
Companion symbolic Python construction for GC-06.04 · Tran Quang Hung & Elliot McGucken’s Three Tangent Circles (GC-06.04).
Programmatic Usage¶
from geometor.divine.catalog import build_construction
model, cert = build_construction("GC-06.04")
assert cert.ratio_expr == sp.GoldenRatio
Exact Builder Implementation¶
def build_tran_mcgucken_three_tangent_circles() -> ConstructionResult:
"""Tran Quang Hung & Elliot McGucken's three mutually tangent equal circles."""
m = new_catalog_model("tran-mcgucken-three-tangent-circles")
s3 = sp.sqrt(3)
O = m.set_point(0, 0, classes=["given"], ID="O")
A = m.set_point(0, 2 * s3 / 3, classes=["given"], ID="A")
B = m.set_point(-1, -s3 / 3, ID="B")
C = m.set_point(1, -s3 / 3, ID="C")
D = m.set_point(0, -s3 / 3, classes=["golden"], ID="D")
E = m.set_point(sp.Rational(1, 2), s3 / 6, ID="E")
F = m.set_point(-sp.Rational(1, 2), s3 / 6, classes=["golden"], ID="F")
_ = E
m.construct_polygon([A, B, C], classes=["auxiliary"], ID="ABC")
m.construct_circle(A, F, classes=["compass"], ID="cA")
m.construct_circle(B, D, classes=["compass"], ID="cB")
m.construct_circle(C, D, classes=["compass"], ID="cC")
c_o = m.construct_circle(O, A, classes=["primary"], ID="cO")
ln_df = m.construct_line(D, F, classes=["golden"], ID="DF")
m.intersect(c_o, ln_df, beyond=(D, F), classes=["golden"], ID="G")
J = m.intersect(c_o, ln_df, beyond=(F, D), classes=["golden"], ID="J")
_ = J
return make_result(m, ("D", "F"), ("F", "G"), ("D", "F", "G"))
Exact Symbolic Point Coordinates¶
All points in tran-mcgucken-three-tangent-circles are certified free of floating-point approximations over \(\mathbb{Q}(\sqrt{3}, \phi)\):
Point |
Exact \(x\) |
Exact \(y\) |
|---|---|---|
|
\(0\) |
\(0\) |
|
\(0\) |
\(\frac{2 \sqrt{3}}{3}\) |
|
\(-1\) |
\(- \frac{\sqrt{3}}{3}\) |
|
\(1\) |
\(- \frac{\sqrt{3}}{3}\) |
|
\(0\) |
\(- \frac{\sqrt{3}}{3}\) |
|
\(\frac{1}{2}\) |
\(\frac{\sqrt{3}}{6}\) |
|
\(- \frac{1}{2}\) |
\(\frac{\sqrt{3}}{6}\) |
|
\(- \frac{\sqrt{5}}{4} - \frac{1}{4}\) |
\(\frac{- \sqrt{3} + 3 \sqrt{15}}{12}\) |
|
\(- \frac{1}{4} + \frac{\sqrt{5}}{4}\) |
\(\frac{- 3 \sqrt{15} - \sqrt{3}}{12}\) |
Certified Golden Ratio: DF / FG = GoldenRatio.