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Posts tagged 'claudius-ptolemy'

GC-05.01 — Claudius Ptolemy's Regular Pentagon & Pentagram (Almagest I.10) cO: x**2 + y**2 - 1 = 0 cMC: y**2 + (x - 1/2)**2 - 5/4 = 0 AB: y = 0 P1P4: y - sqrt(5)/4 + 1/4 = 0 CP2: x*(sqrt(5)/4 + 5/4) - y*sqrt(10 - 2*sqrt(5))/4 + sqrt(10 - 2*sqrt(5))/4 = 0 CP3: x*(sqrt(5)/4 + 5/4) + y*sqrt(10 - 2*sqrt(5))/4 - sqrt(10 - 2*sqrt(5))/4 = 0 Golden major P1K2 = sqrt(2)*sqrt(5 - sqrt(5))/2 Golden minor K2P4 = sqrt(5 - 2*sqrt(5)) A = (-1, 0) C = (0, 1) M = (1/2, 0) E = (1/2 - sqrt(5)/2, 0) P2 = (-sqrt(2)*sqrt(5 - sqrt(5))/4, -sqrt(5)/4 - 1/4) P3 = (sqrt(2)*sqrt(5 - sqrt(5))/4, -sqrt(5)/4 - 1/4) K1 = (-3*sqrt(2)*sqrt(5 - sqrt(5))/8 + sqrt(10)*sqrt(5 - sqrt(5))/8, -1/4 + sqrt(5)/4) O = (0, 0) B = (1, 0) P1 = (-sqrt(10)*sqrt(5 - sqrt(5))/8 - sqrt(2)*sqrt(5 - sqrt(5))/8, -1/4 + sqrt(5)/4) P4 = (sqrt(2)*sqrt(5 - sqrt(5))/8 + sqrt(10)*sqrt(5 - sqrt(5))/8, -1/4 + sqrt(5)/4) K2 = (-sqrt(10)*sqrt(5 - sqrt(5))/8 + 3*sqrt(2)*sqrt(5 - sqrt(5))/8, -1/4 + sqrt(5)/4) A C M E P2 P3 K1 O B P1 P4 K2

GC-05.01 · Claudius Ptolemy’s Regular Pentagon & Pentagram (Almagest I.10)

In unit circle cO with perpendicular radii OB and OC, let M bisect OB. Circle cMC cuts AB at E with \(|OB|/|EO| = \phi\) and chord \(|CE|\) equal to the side of inscribed regular pentagon CP1P2P3P4, whose pentagram diagonals P1P4, CP2, CP3 cut one another in golden chains \(|P1K2|/|K2P4| = \phi\).
05-pentagons-polygons field-pentagonal golden-chain claudius-ptolemy euclid
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