GC-02.07 · Butterfly Chords Astride an Equilateral Triangle

Discoverer(s): Nguyen Thanh Dung | Date: 2016 | Field: \(\mathbb{Q}(\sqrt{3}, \phi)\) | Loci: 6 (Lemoine \(S = 18\))

Let I be the midpoint of radius OJ of circle cO, XT the chord perpendicular to OJ through I, and ICD an equilateral triangle symmetric about OJ with C and D on cO. If rays CI and DI meet cO again at A and B, then chords BC and AD cut XT at Y and Z with \(|YZ|/|ZT| = |YT|/|YZ| = |YZ|/|XY| = \phi\).
GC-02.07 — Butterfly Chords Astride an Equilateral Triangle cO: x**2 + y**2 - 4 = 0 XT: y - 1 = 0 IC: x*(3/4 + 3*sqrt(5)/4) + y*(-sqrt(15)/4 - sqrt(3)/4) + sqrt(3)/4 + sqrt(15)/4 = 0 ID: x*(3/4 + 3*sqrt(5)/4) + y*(sqrt(3)/4 + sqrt(15)/4) - sqrt(15)/4 - sqrt(3)/4 = 0 AD: x*(-3*sqrt(10*sqrt(5) + 30)/16 + 3*sqrt(5)/4 + 15*sqrt(2*sqrt(5) + 6)/16) + y*(-5*sqrt(6*sqrt(5) + 18)/16 + sqrt(30*sqrt(5) + 90)/16 + sqrt(3)/2 + sqrt(15)/4) - 7*sqrt(30*sqrt(5) + 90)/16 - sqrt(3)/8 + sqrt(15)/8 + 5*sqrt(6*sqrt(5) + 18)/16 = 0 BC: x*(-3*sqrt(10*sqrt(5) + 30)/16 + 3*sqrt(5)/4 + 15*sqrt(2*sqrt(5) + 6)/16) + y*(-sqrt(15)/4 - sqrt(3)/2 - sqrt(30*sqrt(5) + 90)/16 + 5*sqrt(6*sqrt(5) + 18)/16) - 5*sqrt(6*sqrt(5) + 18)/16 - sqrt(15)/8 + sqrt(3)/8 + 7*sqrt(30*sqrt(5) + 90)/16 = 0 Golden major YZ = sqrt(30)*sqrt(-5*sqrt(2)*sqrt(sqrt(5) + 3) - sqrt(10)*sqrt(sqrt(5) + 3) + 6*sqrt(5) + 18)/10 Golden minor ZT = sqrt(15)*sqrt(-10*sqrt(2)*sqrt(sqrt(5) + 3) - sqrt(5) + 19 + 3*sqrt(10)*sqrt(sqrt(5) + 3))/10 I = (0, 1) X = (-sqrt(3), 1) C = (-sqrt(15)/4 - sqrt(3)/4, 1/4 - 3*sqrt(5)/4) D = (sqrt(3)/4 + sqrt(15)/4, 1/4 - 3*sqrt(5)/4) A = (-sqrt(30)*sqrt(sqrt(5) + 3)/16 - sqrt(3)/4 + 5*sqrt(6)*sqrt(sqrt(5) + 3)/16, -3*sqrt(10)*sqrt(sqrt(5) + 3)/16 + 1/4 + 15*sqrt(2)*sqrt(sqrt(5) + 3)/16) B = (-5*sqrt(6)*sqrt(sqrt(5) + 3)/16 + sqrt(3)/4 + sqrt(30)*sqrt(sqrt(5) + 3)/16, -3*sqrt(10)*sqrt(sqrt(5) + 3)/16 + 1/4 + 15*sqrt(2)*sqrt(sqrt(5) + 3)/16) O = (0, 0) J = (0, 2) T = (sqrt(3), 1) Y = ((-2*sqrt(15) - 2*sqrt(3) + 2*sqrt(30)*sqrt(sqrt(5) + 3))/(-5*sqrt(2)*sqrt(sqrt(5) + 3) - 4*sqrt(5) + sqrt(10)*sqrt(sqrt(5) + 3)), 1) Z = ((-2*sqrt(30)*sqrt(sqrt(5) + 3) + 2*sqrt(3) + 2*sqrt(15))/(-5*sqrt(2)*sqrt(sqrt(5) + 3) - 4*sqrt(5) + sqrt(10)*sqrt(sqrt(5) + 3)), 1) I X C D A B O J T Y Z

Given & Constructive Steps

Given: Circle cO centered at O \(= (0, 0)\) through J \(= (0, 2)\) with radius midpoint I \(= (0, 1)\).

step Draw chord XT through I perpendicular to OJ, meeting cO at X \(= (-\sqrt{3}, 1)\) and T \(= (\sqrt{3}, 1)\).
step Inscribe equilateral triangle ICD with apex I and base vertices C, D on cO.
step Extend CI and DI to meet cO at A and B, then draw butterfly chords BC and AD cutting XT at Y and Z.

Exact Symbolic Proof & Certificate

For C and D on \(x^2 + y^2 = 4\) forming equilateral ICD of side \(s\) below I \(= (0, 1)\), \((s/2)^2 + (1 - s\sqrt{3}/2)^2 = 4 \implies s^2 - \sqrt{3}\,s - 3 = 0\), giving \(s = \sqrt{3}\,\phi\) directly. By the Butterfly Theorem and symmetry across OJ, \(|IY| = |IZ| = \sqrt{3}/(2\phi)\), while \(|IT| = \sqrt{3}\). Hence \(|YZ| = \sqrt{3}/\phi\) and \(|ZT| = \sqrt{3}(1 - 1/(2\phi))\)—moreover \(|YZ|/|ZT| = |YT|/|YZ| = |YZ|/|XY| = \phi\), forming the 4-point golden chain \((X, Y, Z, T)\).

Machine-Verified Symbolic Certificate

Invariant

Exact Symbolic Value

Primary Golden Ratio

YZ \(/\) ZT \(= \frac{1}{2} + \frac{\sqrt{5}}{2}\) on collinear triple (Y, Z, T)

Exact Segment Lengths

\(|YZ| = \frac{\sqrt{30} \sqrt{- 5 \sqrt{2} \sqrt{\sqrt{5} + 3} - \sqrt{10} \sqrt{\sqrt{5} + 3} + 6 \sqrt{5} + 18}}{10}\), \(|ZT| = \frac{\sqrt{15} \sqrt{- 10 \sqrt{2} \sqrt{\sqrt{5} + 3} - \sqrt{5} + 19 + 3 \sqrt{10} \sqrt{\sqrt{5} + 3}}}{10}\)

Rational Trigonometry Quadrances

\(Q(Y, Z) = \frac{- 15 \sqrt{2} \sqrt{\sqrt{5} + 3} - 3 \sqrt{10} \sqrt{\sqrt{5} + 3} + 18 \sqrt{5}}{10} + \frac{27}{5}\), \(Q(Z, T) = \frac{- 30 \sqrt{2} \sqrt{\sqrt{5} + 3} - 3 \sqrt{5} + 9 \sqrt{10} \sqrt{\sqrt{5} + 3}}{20} + \frac{57}{20}\), \(Q_{\text{long}}/Q_{\text{short}} = \frac{\sqrt{5}}{2} + \frac{3}{2} = \phi^2\)

Algebraic Number Field

\(\mathbb{Q}(\sqrt{3}, \phi)\)

Géométrographie Loci

2 given points · 5 lines · 1 circles · 1 polygons (elementary loci \(= 6\), Lemoine \(S = 18\))

Automated Divine Scan

geometor.divine.golden detected 2 exact collinear golden section(s) and 1 connected golden chain(s) in this model:

  • Section (X, Y, Z): long \(|YZ|^2 = \frac{- 15 \sqrt{2} \sqrt{\sqrt{5} + 3} - 3 \sqrt{10} \sqrt{\sqrt{5} + 3} + 18 \sqrt{5}}{10} + \frac{27}{5}\) vs. short \(|XY|^2 = \frac{- 30 \sqrt{2} \sqrt{\sqrt{5} + 3} - 3 \sqrt{5} + 9 \sqrt{10} \sqrt{\sqrt{5} + 3}}{20} + \frac{57}{20}\)

  • Section (Y, Z, T): long \(|YZ|^2 = \frac{- 15 \sqrt{2} \sqrt{\sqrt{5} + 3} - 3 \sqrt{10} \sqrt{\sqrt{5} + 3} + 18 \sqrt{5}}{10} + \frac{27}{5}\) vs. short \(|ZT|^2 = \frac{- 30 \sqrt{2} \sqrt{\sqrt{5} + 3} - 3 \sqrt{5} + 9 \sqrt{10} \sqrt{\sqrt{5} + 3}}{20} + \frac{57}{20}\)

Connected Golden Chains:

  • Chain (X — Y — Z — T) spanning 2 overlapping golden sections (progression < >)

Historical Commentary & Attribution

Discovered by Nguyen Thanh Dung (Cut-the-Knot), this synthesis of Odom’s equilateral chord and the classical Butterfly Theorem creates four collinear points \((X, Y, Z, T)\) with three overlapping golden sections on XT.