Unit V: Axial Reflection & Chapter III — The Theory of Revolution — Notes¶
Historical, Mathematical & Cross-Repository Commentary (pp. 60–68)
Historical, Mathematical & GEOMETOR Commentary¶
1. Petersen’s Theory of Revolution as Complex Multiplication¶
Petersen’s Chapter III (pp. 65–68) is one of the earliest and cleanest elementary expositions of planar spiral similarity. Placing the pivot point \(O\) at \(0 \in \mathbb{C}\), Petersen’s revolution \((O, v, f)\) is multiplication by the complex constant \(\lambda = f e^{i v}\):
Look at how transparently this explains § 5 (Miquel’s Pivot Point, p. 68) and Problem 349 (p. 67):
Any non-translation direct similarity \(z \mapsto \lambda z + \mu\) (\(\lambda \neq 1\)) has a unique fixed point \(z_O = \mu / (1 - \lambda)\)—Petersen’s pivot point, constructed synthetically via the Miquel circles \((PAa) \cap (PBb)\).
In Problem 349 (equilateral triangle with vertices on three parallel lines \(L_1, L_2, L_3\)), multiplication around \(P \in L_1\) by \(e^{i\pi/3} = \frac{1 + i\sqrt{3}}{2}\) (\(v = 60^\circ, f = 1\)) maps \(Q \in L_2\) to \(R \in e^{i\pi/3}(L_2) \cap L_3\), solving the problem in a single line-line intersection!
2. Porismatic Parity in Problem 340 (Minimum-Perimeter Inscribed Polygons)¶
In Problem 340 (p. 62), unfolding an inscribed \(n\)-gon across the \(n\) sides of a host \(n\)-gon composes \(n\) axial reflections:
When \(n\) is odd, the product of \(n\) reflections is an orientation-reversing glide/reflection, yielding a unique determinate fixed-direction cycle (for \(n = 3\) in an acute triangle, Fagnano’s 1775 orthic triangle, pedal of orthocenter
X(4)).When \(n\) is even, the product of \(n\) reflections is an orientation-preserving rotation or translation: if a non-trivial rotation, no parallel periodic path exists (
0solutions); if a pure translation (e.g. a cyclic quadrilateral whose opposite angles match, or a billiard rectangle), infinitely many equal-perimeter inscribed polygons exist!
3. Exact geometor.model Realizations: equilateral_on_three_parallels & hero_reflection_shortest_path¶
equilateral_on_three_parallels()(Problem 349, p. 67): On \(y_1 = 0, y_2 = 1, y_3 = 3\) with pivot \(P = (0, 0)\), rotating \(L_2\) by \(+60^\circ\) via Euclid I.1 circles produces \(L'_2: \sqrt{3}\,x - y + 2 = 0\), meeting \(L_3\) at \(R = (\frac{\sqrt{3}}{3}, 3)\) and rotating back to \(Q = (\frac{5\sqrt{3}}{3}, 1)\) in \(\mathbb{Q}(\sqrt{3})\). All three side quadrances equal \(\frac{28}{3}\), and all interior spreads equal \(\frac{3}{4}\) (\(\sin^2 60^\circ\)).hero_reflection_shortest_path()(Problem 338, p. 61): Reflecting \(A = (2, 6)\) across \(y = 0\) to \(A_1 = (2, -6)\) and joining \(A_1\) to \(B = (14, 10)\) meets the mirror at \(X = (\frac{13}{2}, 0)\) with equal incidence/reflection spreads \(\frac{16}{25}\) and minimum unfolded path quadrance \(Q(A_1, B) = 12^2 + 16^2 = 400 = 20^2\).
Cross-Repository Concordance Links¶
(See the full Petersen Master Concordance for complete tables, and demos for executable SymPy demonstrations.)
Chapter II.B, Replacing & Revolution Around an Axis (pp. 56–64) (Problems 311, 316, 317, 336, 338, 339, 340) (Replacing, Hero’s Mirror Reflection & Minimum-Perimeter Inscribed Polygons (Chapter II.B, Replacing & Revolution Around an Axis (pp. 56–64))): Flips or rescales sub-figures to make unknown equal/proportional edges cover one another (Ptolemy cyclic quadrilateral Problem 316), and reflects across a symmetry axis to solve Hero’s optical path (Problem 338), polygonal billiards (Problem 339), and Fagnano/minimum-perimeter inscribed polygons (Problem 340). - : Direct continuation of Petersen’s Revolution Around an Axis. - : For acute triangles, Petersen’s Problem 340 (minimum-perimeter inscribed polygon, p. 62) yields the orthic pedal triangle.
Chapter III, The Theory of Revolution §§ 1–5 (pp. 65–68) (Problems 349, 350, 352, 357) (Spiral Similarity (O, v, f), 60° Rotation on Three Parallels & the Pivot Point (Chapter III, The Theory of Revolution §§ 1–5 (pp. 65–68))): Introduces planar spiral similarity (pivot point O, angle of revolution v, ratio of revolution f = OA/Oa), solves placing an equilateral triangle on three parallel lines or concentric circles via v = 60°, f = 1 (Problems 349–350), and constructs the Miquel pivot point of two similar figures (§ 5, p. 68). - : Adapts Petersen’s 60° and 90° rotation constructions (Problems 349–350) into standard synthetic exercises.