Unit IV — The Ten Neo-Pythagorean Means & the Cube’s Most Perfect Proportion — Structural Map¶
Semicircle Geometry, the Decad of Means & the Cube’s Teleiotatē Analogia · Book II, Chs. 21–29
Architectural Thesis¶
Unit IV crowns the Introductio Arithmetica by uniting arithmetic, geometry, stereometry, and harmonics in the theory of means:
The Three Classical Means & Semicircle Identity (II.21–27): Arithmetic (\(A = \frac{a+c}{2}\)), Geometric (\(G = \sqrt{ac}\)), and Harmonic (\(H = \frac{2ac}{a+c}\)) means satisfy \(H \le G \le A\) and the exact geometric mean law \(G^2 = A \cdot H\), constructed on semicircle PR via radius OR = A, ordinate QS = G, and projection QF = H.
The Complete Decad of Ten Proportions (II.28): Adding the three subcontrary means (4–6) and the four outer-difference means of Myonides and Euphranor (7–10) completes the Pythagorean Decad, culminating in Mean 10 (3, 5, 8) where \(a + b = c\).
The Most Perfect Proportion 6 : 8 :: 9 : 12 (II.29): Built upon Philolaus's Cube (6 faces, 8 vertices, 12 edges), the four-term teleiotatē analogia embeds Arithmetic (\(9\)), Harmonic (\(8\)), and Geometric (\(6 \cdot 12 = 8 \cdot 9 = 72\)) symmetry alongside the octave 2:1, fifth 3:2, fourth 4:3, and whole tone 9:8.
Synoptic Table of the Ten Means¶
# |
Defining Proportion (\(a < b < c\)) |
Closed Formula for \(b\) |
Canonical Triple |
|---|---|---|---|
1 |
\((c - b) : (b - a) = 1 : 1\) (Arithmetic) |
\(b = \frac{a + c}{2}\) |
\((1, 2, 3)\) / \((6, 9, 12)\) |
2 |
\((c - b) : (b - a) = c : b = b : a\) (Geometric) |
\(b = \sqrt{ac}\) |
\((1, 2, 4)\) / \((4, 6, 9)\) |
3 |
\((c - b) : (b - a) = c : a\) (Harmonic) |
\(b = \frac{2ac}{a + c}\) |
\((3, 4, 6)\) / \((6, 8, 12)\) |
4 |
\((c - b) : (b - a) = a : c\) (Subcontrary) |
\(b = \frac{a^2 + c^2}{a + c}\) |
\((3, 5, 6)\) |
5 |
\((c - b) : (b - a) = a : b\) |
\(b = \frac{c - a + \sqrt{(c-a)^2 + 4a^2}}{2}\) |
\((2, 4, 5)\) |
6 |
\((c - b) : (b - a) = b : c\) |
\(b = \frac{a - c + \sqrt{(c-a)^2 + 4c^2}}{2}\) |
\((1, 4, 6)\) |
7 |
\((c - a) : (b - a) = c : a\) |
\(b = \frac{a^2 + ac - a^2 \text{ [}2ac - a^2\text{]}}{c} = \frac{a(2c - a)}{c}\) |
\((6, 8, 9)\) |
8 |
\((c - a) : (c - b) = c : a\) |
\(b = \frac{a^2 + c^2 - ac}{c}\) |
\((6, 7, 9)\) |
9 |
\((c - a) : (b - a) = b : a\) |
\(b = \frac{a + \sqrt{a(4c - 3a)}}{2}\) |
\((4, 6, 7)\) (corr.) |
10 |
\((c - a) : (c - b) = b : a\) (Fibonacci) |
\(b = c - a \iff a + b = c\) |
\((3, 5, 8)\) |