.. index:: construction, perpendicular .. _I.11: .. _construct perpendicular from point on line: construct perpendicular from point on line ========================================== I.11 To draw a straight line at right angles to a given straight line from a given point on it. -- Euclid .. image:: elem.1.prop.11.png :align: right :width: 300px Let `AB` be the given straight line, and `C` the given point on it. **PROBLEM:** draw from the point `C` a straight line at right angles to the straight line `AB`. Let a point `D` be taken at random on `AC`; [1]_ let `CE` be made equal to `CD`; [I.3] on `DE` let the equilateral triangle `FDE` be constructed, [I.1] and let `FC` be joined; I say that the straight line `FC` has been drawn at right angles to the given straight line `AB` from `C` the given point on it. For, since `DC` is equal to `CE`, and `CF` is common, - the two sides `DC`, `CF` are equal to the two sides `EC`, `CF` respectively; and the base `DF` is equal to the base `FE`; - therefore the angle `DCF` is equal to the angle `ECF`; [I.8] and they are adjacent angles. But, when a straight line set up on a straight line makes the adjacent angles equal to one another, each of the equal angles is right; [I.def.10] - therefore each of the angles `DCF`, `FCE` is right. Therefore the straight line `CF` has been drawn at right angles to the given straight line `AB` from the given point `C` on it. - Q. E. F. references ---------- [I.def.10]: /elem.1.def.10 "Book I - Definition 10" [I.1]: /elem.1.1 "Book I - Proposition 1" [I.3]: /elem.1.3 "Book I - Proposition 3" [I.8]: /elem.1.8 "Book I - Proposition 8" footnotes ---------- .. [1] let CE be made equal to CD. The verb is κείσθω which, as well as the other parts of κεῖμαι, is constantly used for the passive of τίθημι to place ; and the latter word is constantly used in the sense of making, e.g., one straight line equal to another straight line.