.. index:: construction, lines .. _I.2: .. _construct equal segments by extension: construct equal segments by extension ===================================== I.2 To place at a given point (as an extremity) a straight line equal to a given straight line. -- Euclid .. image:: construct-equal-segments-by-extension.png :align: right :width: 300px From the given points :math:`A` and :math:`B` :ref:`set segment` :math:`\bar{AB}`. From the given points :math:`C` and :math:`D` :ref:`set segment` :math:`\bar{CD}` shorter than :math:`\bar{AB}`. **PROBLEM:** Extend segment :math:`\bar{CD}` to a length equal to :math:`\bar{AB}` :ref:`construct circle` :math:`(A, B)` as :math:`c_1` .. :ref:`construct circle` :math:`(C, D)` as :math:`c_2` With points :math:`A` and :math:`C` :ref:`construct segment` :math:`\bar{AC}` :ref:`contruct equilateral triangle` on :math:`\bar{AC}` identify new point of equaliteral triangle as :math:`E` :ref:`construct line` :math:`\overline{EA}` :ref:`construct line` :math:`\overline{EC}` Identify new point on :math:`c_1` intersecting with :math:`\overline{EA}` as :math:`F` :ref:`construct circle` :math:`(E, F)`` as :math:`c_2` Identify new point on :math:`c_2` intersecting with :math:`\overline{EC}` as :math:`G` Let the straight lines **AE**, **BF** be produced [2]_ in a straight line with **DA**, **DB**; [I.post.2] with centre **B** and distance **BC** let the circle **CGH** be described; [I.post.3] and again, with centre **D** and distance **DG** let the circle **GKL** be described. [I.post.3] Then, since the point **B** is the centre of the circle **CGH**, :math:`\therefore` **BC** is equal to **BG**. Again, since the point **D** is the centre of the circle **GKL**, :math:`\therefore` **DL** is equal to **DG**. And in these **DA** is equal to **DB**; :math:`\therefore` the remainder **AL** is equal to the remainder **BG** [3]_. [I.c.n.3] But **BC** was also proved equal to **BG**; :math:`\therefore` each of the straight lines **AL**, **BC** is equal to **BG**. And things which are equal to the same thing are also equal to one another; [I.c.n.1] :math:`\therefore` **AL** is also equal to **BC**. :math:`\therefore` at the given point **A** the straight line **AL** is placed equal to the given straight line **BC**. - (Being) what it was required to do. dependencies ------------ [I.def.15]: /elem.1.def.15 "Book I - Definition 15" [I.1]: /elem.1.1 "Book I - Proposition 1" [I.post.1]: /elem.1.post.1 "Book I - Postulate 1" [I.post.2]: /elem.1.post.2 "Book I - Postulate 2" [I.post.3]: /elem.1.post.3 "Book I - Postulate 3" [I.c.n.1]: /elem.1.c.n.1 "Book I - Common Notion 1" [I.c.n.3]: /elem.1.c.n.3 "Book I - Common Notion 3" footnotes --------- .. [1] (as an extremity). I have inserted these words because to place a straight line at a given point (πρὸς τῷ δοθέντι σημείῳ) is not quite clear enough, at least in English. .. [2] Let the straight lines AE, BF be produced.... It will be observed that in this first application of Postulate 2, and again in I. 5, Euclid speaks of the continuation of the straight line as that which is produced in such cases, ἐκβεβλήσθωσαν and προσεκβεβλήσθωσαν meaning little more than drawing straight lines in a straight line with the given straight lines. The first place in which Euclid uses phraseology exactly corresponding to ours when speaking of a straight line being produced is in I. 16: let one side of it, **BC**, be produced to **D** (προσεκβεβλήσθω αὐτοῦ μία πλευρὰ ἡ ΒΓ ἐπὶ τὸ Δ). .. [3] the remainder AL...the remainder BG. The Greek expressions are λοιπὴ ἡ ΑΛ and λοιπῇ τῇ BH, and the literal translation would be **AL** (or **BG**) remaining, but the shade of meaning conveyed by the position of the definite article can hardly be expressed in English.