.. index:: construction, lines
.. _I.2:
.. _construct equal segments by extension:
construct equal segments by extension
=====================================
I.2
To place at a given point (as an extremity) a straight line equal to a given
straight line.
-- Euclid
.. image:: construct-equal-segments-by-extension.png
:align: right
:width: 300px
From the given points :math:`A` and :math:`B` :ref:`set segment`
:math:`\bar{AB}`.
From the given points :math:`C` and :math:`D` :ref:`set segment`
:math:`\bar{CD}` shorter than :math:`\bar{AB}`.
**PROBLEM:** Extend segment :math:`\bar{CD}` to a length equal to :math:`\bar{AB}`
:ref:`construct circle` :math:`(A, B)` as :math:`c_1`
.. :ref:`construct circle` :math:`(C, D)` as :math:`c_2`
With points :math:`A` and :math:`C` :ref:`construct segment` :math:`\bar{AC}`
:ref:`contruct equilateral triangle` on :math:`\bar{AC}`
identify new point of equaliteral triangle as :math:`E`
:ref:`construct line` :math:`\overline{EA}`
:ref:`construct line` :math:`\overline{EC}`
Identify new point on :math:`c_1` intersecting with :math:`\overline{EA}` as :math:`F`
:ref:`construct circle` :math:`(E, F)`` as :math:`c_2`
Identify new point on :math:`c_2` intersecting with :math:`\overline{EC}` as :math:`G`
Let the straight lines **AE**, **BF** be produced [2]_ in a straight line
with **DA**, **DB**; [I.post.2] with centre **B** and distance **BC** let the
circle **CGH** be described; [I.post.3] and again, with centre **D** and
distance **DG** let the circle **GKL** be described. [I.post.3]
Then, since the point **B** is the centre of the circle **CGH**,
:math:`\therefore` **BC** is equal to **BG**.
Again, since the point **D** is the centre of the circle **GKL**,
:math:`\therefore` **DL** is equal to **DG**.
And in these **DA** is equal to **DB**;
:math:`\therefore` the remainder **AL** is equal to the remainder **BG** [3]_.
[I.c.n.3]
But **BC** was also proved equal to **BG**;
:math:`\therefore` each of the straight lines **AL**, **BC** is equal to **BG**.
And things which are equal to the same thing are also equal to one another;
[I.c.n.1]
:math:`\therefore` **AL** is also equal to **BC**.
:math:`\therefore` at the given point **A** the straight line **AL** is placed equal to
the given straight line **BC**.
- (Being) what it was required to do.
dependencies
------------
[I.def.15]: /elem.1.def.15 "Book I - Definition 15"
[I.1]: /elem.1.1 "Book I - Proposition 1"
[I.post.1]: /elem.1.post.1 "Book I - Postulate 1"
[I.post.2]: /elem.1.post.2 "Book I - Postulate 2"
[I.post.3]: /elem.1.post.3 "Book I - Postulate 3"
[I.c.n.1]: /elem.1.c.n.1 "Book I - Common Notion 1"
[I.c.n.3]: /elem.1.c.n.3 "Book I - Common Notion 3"
footnotes
---------
.. [1] (as an extremity).
I have inserted these words because to place a straight line
at a given point
(πρὸς τῷ δοθέντι
σημείῳ) is not quite clear enough, at least in English.
.. [2] Let the straight lines AE, BF be produced....
It will be observed that in this first application of Postulate 2, and again in I.
5, Euclid speaks of the continuation of the straight line as
that which is produced in such cases, ἐκβεβλήσθωσαν and προσεκβεβλήσθωσαν meaning little more than
drawing straight lines in a straight line with
the
given straight lines. The first place in which Euclid uses phraseology
exactly corresponding to ours when speaking of a straight line
being produced is in I. 16: let one side of
it, **BC**, be produced to **D**
(προσεκβεβλήσθω αὐτοῦ μία πλευρὰ ἡ ΒΓ ἐπὶ τὸ Δ).
.. [3] the remainder AL...the remainder BG.
The Greek expressions are λοιπὴ ἡ ΑΛ and
λοιπῇ τῇ BH, and the literal translation
would be **AL** (or **BG**) remaining,
but the shade
of meaning conveyed by the position of the definite article can hardly be
expressed in English.